
The pendulum experiment was conducted on the surface of Mars (g = 3.71 m/s2). The physical pendulum has a length of 1.08 m and a mass of 0.102 kg. If the pendulum length is doubled, then what is the new period?
7. How long must a simple pendulum string be to have a period of 2 seconds on mars where the acceleration due to gravity at the surface is 0.376g.
1. If placed at the surface of Earth, a physical pendulum has a period of 1.8 seconds. What will be the period of the same pendulum at the surface of the Moon (gMoon = 1.62 m/s2)? The period at the Moon's surface, T = Units in s 2. The same pendulum is placed at the surface of an unknown planet X. What is the free fall acceleration at the surface of this planet if the pendulum has a period of 1.17...
. A simple pendulum consists of a 2.0 kg brass bob on a string about 0.5 m long. It has a period of about 1.42 sec. The pendulum would have a period of about 5 seconds if the A. string were replaced by one 25 m long. B. string were replaced by one 6.2 m long. C. bob were replaced by a 0.6 kg brass sphere. D. bob were replaced by a 7.0 kg brass sphere. E. bob was released...
- 0/4 points Previous Answers SerPSE10 15.A.OP.036.MI. The free-fall acceleration on Mars is 3.7 m/s2. (a) What length of pendulum has a period of 1.8 s on Earth? 0.00805 Use the relation between the length of a pendulum and its period, cm (b) What length of pendulum would have a 1.8-s period on Mars? 0.805 Use the relation between the length of a pendulum and its period. cm An object is suspended from a spring with force constant 10 N/m....
An astronaut has a pendulum made of 1.00 m long string and attached mass, which they let oscillate on Earth. They take their pendulum to an unknown planet with radius 71.5 x 10^3 km where the period of oscillation is 1.59 times shorter. a) What is the frequency and period of oscillation of the pendulum on Earth? b) What is the frequency and period of oscillation of the pendulum on unknown planet? c) What is the gravitational acceleration of the...
ans: 12.8 m/s^2
You crash land your spaceship on a mysterious planet. You want to figure out g, the acceleration due to gravity, on the surface of the planet. Fortunately, you brought a stopwatch and simple pendulum: a 75.0 centimeter long string tied to a 1.50 kg mass. You measure the period of the pendulum to be 1.52 seconds. What is the value of g, in units of m/s2? Assume there is no air resistance as the pendulum swings.
1. How much is the period of 1=1.00 m long pendulum on the Moon (g = 1.600 m/s2) 4.97 sec. 2. On a planet X pendulum of the length 0.500 m makes 50.0 oscillations in 1.00 min. Find the acceleration of gravity on the planet X. g = 13.7 m/s2. 3. Find the period of small oscillations of a meter stick suspended by its end near Earth surface (assume g=9.800 m/s2). Notice that this is not a simple pendulum but...
A simple pendulum with mass m = 1.8 kg and length L = 2.77 m hangs from the ceiling. It is pulled back to an small angle of θ = 9° from the vertical and released at t = 0. 1) What is the period of oscillation? Answer= 3.34 s 2) What is the magnitude of the force on the pendulum bob perpendicular to the string at t=0? Answer= 2.76 N 3) What is the maximum speed of the pendulum?...
A pendulum has a period of 1.71 s on Earth.
What is its period on Mars, where the acceleration of gravity is
about 0.37 that on Earth?
An unfingered guitar string is 0.68 m long and is tuned to play
E above middle C (330 Hz).
How far from the nut of the guitar must a fret (and your finger)
be placed on this string to play F♯ (370 Hz)?
A pendulum has a period of 1.71 s on Earth. Part...