The pendulum experiment was conducted on the surface of Mars (g = 3.71 m/s2). The physical pendulum has a length of 1.08 m and a mass of 0.102 kg. If the pendulum length is doubled, then what is the new period?


answers got in the two different ways are consistent. please do check your options.
The pendulum experiment was conducted on the surface of Mars (g = 3.71 m/s2). The physical...
1. If placed at the surface of Earth, a physical pendulum has a period of 1.8 seconds. What will be the period of the same pendulum at the surface of the Moon (gMoon = 1.62 m/s2)? The period at the Moon's surface, T = Units in s 2. The same pendulum is placed at the surface of an unknown planet X. What is the free fall acceleration at the surface of this planet if the pendulum has a period of 1.17...
0 ti The a 7. g on the surface of the Mars is 3.73 m/s2. A pendulum consists of a 25 gram bob an string. How long must the string be for the period of oscillation to be 3 seconds?
- 0/4 points Previous Answers SerPSE10 15.A.OP.036.MI. The free-fall acceleration on Mars is 3.7 m/s2. (a) What length of pendulum has a period of 1.8 s on Earth? 0.00805 Use the relation between the length of a pendulum and its period, cm (b) What length of pendulum would have a 1.8-s period on Mars? 0.805 Use the relation between the length of a pendulum and its period. cm An object is suspended from a spring with force constant 10 N/m....
In the experiment conducted on Earth a pendulum is found to have period equal to 1 s, and a spring-box oscillator (oscillating on a level frictionless surface) is found to have the same period of 1 s. Both objects are taken to Mars. The experiment is repeated on the surface of Mars. It is found that the pendulum has period Tr, and that the spring-box oscillator has period TSB. Gravitational acceleration on Mars is gM = 3.7 m/s Which one...
1. Consider a physical pendulum with length 0.68 m and mass 0.200 kg. If the pendulum was released form an angle of 10*, then calculate the angular speed of the pendulum. (gravity= 9.8 m/s^2). [I tried using the formula: 2pi/L to get 2pi/0.68 = 9.24 but this is NOT correct.] 2. Suppose that you are on an unknown planet in a distant galaxy. Let the length of a physical pendulum be 0.53 m. In the physical pendulum experiment, the period...
Ch 14 HW Exercise 14.48 Part A A certain simple pendulum has a period on the earth of 1.50 s What is its period on the surface of Mars, where g = 3.71 m/s2? Request Answer Provide Feedback
Consider a physical pendulum with length of 0.59 m and mass of 0.200 kg. If the pendulum was released from an angle of 10o, then calculate the angular speed of the pendulum. (g = 9.80 m/s2)
A certain simple pendulum has a period on earth of 1.72 s. What is its period on the surface of Mars,where the acceleration due to gravity is 3.71 m/s2 ?
A certain simple pendulum has a period on the earth of 2 s What is its period on the surface of Mars , where g+3.71 m/s^2
Problem 3 A simple pendulum on Earth has a period of 1.60 s. What is its period on the surface of Mars, where g = 3.71 m/s??