Question

NET IONIC REACTIONS: Fill in the balanced net ionic reactions for each step of the experiment listed below: For example, Part A: Cu + 4H + 2 NOs Cu 2 NO2 2H20 Part B: 2 OH +Cu+ Part D: Part E:

Answer 1

Part B)

2OH- + Cu²⁺ -----> Cu (OH)₂

No of oxygen atom,no of copper atom,number of H atom is equal as well as charge is also equal.

Part C)

Cu (OH)2 +2H⁺ -----> Cu²⁺ +2 H2O

Here we know that the no of atoms are not equal in this case so we have to balance the ionic equation.

Cu (OH)2 + 2H⁺---> Cu²⁺ + H2O

So in first step add H2O in Right side to equal number of oxygen atom.

Cu (OH)2+ 2H⁺--->Cu²⁺ + H2O+H2O

Second we know that have to add H⁺ to balance the number of Hydrogen atom.

Cu (OH)2+ 2H⁺ ----> Cu²⁺ + 2H2O

Now this is the balanced equation

So in part D) put Cu (OH)2 + 2H⁺ in blank space

Part E)

Net ionic reaction is

Cu (OH)2 + 2OH^- + 2H⁺ -----> Cu (OH)2 + 2H2O