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4) a. In the regulator shown in figure 6, R: -60K0, R = 45KN and V2 = 5.8V. If the 12 V output drops 0.2 V, calculate the cha
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change in UBE2) = IUBE @4 V=5.8V Vo = 12V to 0.2 A UBEZ? when vo=12V VO*R2 nor RIHRL 12+ 45 45+60 UR₂ = 5.140 Zenor diode in Powu dissipation of Q,95 46 2 VO - lov I = 180mA IRL = VO VO 10 Ich RL 곤 180 R = 5505562 Pliss = NIE, I c - UCED I VCG= UC-UE

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