Given sigma={a, b} And languages L1, L2 contain in sigma^* I need to prove/disprove the following claim: 
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Given sigma={a, b} And languages L1, L2 contain in sigma^* I need to prove/disprove the following claim:
For Language L1 and L2 prove or disprove (L1 union L2)*=L1* intersection L2*
Which of the following languages are regular. Prove (by providing a regular expression) or disprove. a. L1 = {ai bj ck dl | (i + j)mod 2 = (k + l)mod 2 , i, j, k, l ≥ 0} b. L2 = {ai bj ck dl | (i + j) = (k + l), i, j, k, l ≥ 0}
14.) Let L1 = L(a∗baa∗) and L2 = L(aba∗). Find L1/L2. This is a Formal Languages and Automata question... I need to see what the dfa for L1/L2 looks like and how you know what the final states are... Thanks!
Prove that If L1 is linear and L2 is regular, L1×L2 is a linear Language.
disprove that the given lan 4. [20 Points For each of the following languages, prove or guage is regular (a) L1www e {a,b}*} {w w E {a, b}* and no two b's in w have odd number of a's in between}. (b) L2 (c) L3 a" (d) L4 vw n = 3k, for k > 0}. a, b}*}
disprove that the given lan 4. [20 Points For each of the following languages, prove or guage is regular (a) L1www e...
a) if L1 is recognisable but not decidable, L2 is decidable but not recognisable, then prove L1 U L2 is undecidable? b) if L1 is recognisable but not decidable, L2 is recognisable but not decidable, then prove L1 U L2 is undecidable?
Automata, Languages and Computation
Using the languages L1 = { (10)* 1(1+0) + (10)*} and L2 = { a(a*) }, construct an ei NFA that accepts the concatenation of the languages L1L2.
Using the languages L1 = { (10)* 1(1+0) + (10)*} and L2 = { a(a*) }, construct an ei NFA that accepts the concatenation of the languages L1L2.
For each of the following statements, where L1, L2, and L are languages over some alphabet Σ, state whether it is true or false. Prove your answer. • ∀L,(∅ or L+) = L∗ • ∀L1,L2,(L1 or L2)∗ = (L2 or L1)∗
2. If L1 and L2 are regular languages, which of the following are regular languages? Provide justification for your answers. a. L1 U L2 b. L1L2 c. L1 n L2