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A volleyball is spiked so that its incoming velocity of +3.04 m/s is changed to an...

A volleyball is spiked so that its incoming velocity of +3.04 m/s is changed to an outgoing velocity of -18.2 m/s. The mass of the volleyball is 0.350 kg. What is the magnitude of the impulse that the player applies to the ball?

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Answer #1

Impulse = change in momentum = m (v2 - v1)

Impulse = (0.350 kg) (-18.2 m/s - 3.04 m/s)

Impulse = - 7.434 kg m/s

Magnitude of impulse = 7.434 kg m/s

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