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CODE:
#include <stdio.h>
unsigned long long int factorial(int num){
if(num==1){
return 1;
}
return num*factorial(num-1);
}
int main()
{
printf("%llu\n",factorial(5));
printf("%llu\n",factorial(20));
return 0;
}
SCREENSHOT :

OUTPUT :

C programming KAM5 Write a function unsigned long long int factorial(int num) to compute the factorial...
C++ //Write prototype for function factorial that accepts an int num and returns an int /* WITH LOOP OF YOUR CHOICE: Write code for function factorial that accepts an int num and returns the num's factorial factorial(5); 1*2*3*4*5 returns 120 DON'T FORGET TO WRITE TEST CASE. */ //write includes statements //write using statements for cin and cout /* Use a do while loop to prompt the user for a number, call the factorial function, and display the number's factorial. Also,...
#include <stdio.h> int isValidCC(unsigned long long int CCNumber); int main() { unsigned long long int CCNumbers[] = { 4388576018410707ULL, // valid 4388576018402626ULL, // invalid 7388576018402686ULL, // invalid 438857601810707ULL, // invalid 4012888888881881ULL // valid }; for (int i = 0; i < sizeof(CCNumbers) / sizeof(CCNumbers[0]); i++) { if (isValidCC(CCNumbers[i])) { printf("%llu is a valid Visa number.\n", CCNumbers[i]); } else { printf("%llu is not a valid Visa number.\n", CCNumbers[i]); } } } int isValidCC(unsigned long long int CCNumber) { // TO DO...
10.11 (Left Shifting Integers ) Left shifting an unsigned int by
1 bit is equivalent to multiplying the value by 2. Write function
power2 that takes two integer arguments number and pow and
calculates number * 2pow. You should declare pow as an unsigned
integer , but remember that the result may be a negative value .
Use the shift operator to calculate the result. Print the values as
integers and as bits . Assume that an integer is of...
The language has to be in C program
1. (a) rite a function, int factorial (int n), which returns n (the factorial of n, i e. 1 x2 x3 x...xn.) (b) Using int factorial (int n) above, write a program to compute 2. We want to find one of the roots of a cubic equation given by which is between 0 and 1 by an iterative method. Modify the equation above to 1 x Start with an appropriate initial value...
(use only variables, expression, conditional statement and loop
of c programming)
***C programming**
int sum_of_cubes(int n) {
}
int quadrant(int x, int y) {
}
int num_occurrences_of_digit(long num, int digit) {
return 0;
}
3.1 int sum_of_cubes(int n) This function should return the sum of the cubes of the first n integers. For example, if n is 4, it should return 13 +23+ 39 +4°. There is a simple formula for the result: 3x = ((n + 1)) = +...
rite a c funetion to find factorial of a nunbez. The factorial of a positive nunber n is given by: factorial of n (n!)1*23*4....n copy the following code, then finish the progran <stdio.h> #include Define a function factorial to return the factorial of n (n!) long int factorial (int n) // your code int mainO int n; printf ("please input n:") scanf ("%d", &n); printf (d! %1dn, n, factorial (n)) return 0
Write a C function named f such that … the prototype of function f is … unsigned long int f ( unsigned long int X, unsigned long int Y ) function f returns … the nonnegative integer Z such that X 2 + Y 2 = Z 2 if such a nonnegative integer Z exists zero if there is no nonnegative integer Z such that X 2 + Y 2 = Z 2 Example 1 If X = 3 and Y = 4 ...
Solve using C programming
3. lf you are given this code. #include <stdio.h> int main() int var1, var2; int sum; printf("Enter number 1:\n "); scanf("%d",&var1); printf("Enter number 2:In ); scanf("%d",&var2); sum-var1+var2; printf ("Vnsum of two entered numbers : %d", //printf ("Output: %d", res); sum); return e; Modify this code by creating a function called "addition". Make the arguments of the functions numberl and number 2. Add the two values in the function. Return a value called "result". Print "result" in...
Write a program in C++ that implements a function // Precondition: num >= 0 int rotateUp(int num); which produces a new integer with each digit replaced with (digit+1), and 9 replaced with 0, because we don’t have digit 10: rotateUp(5) == 6 rotateUp(17) == 28 rotateUp(126) == 237 rotateUp(5091) == 6102 rotateUp(9911) == 22 // technically, more like 0022 The program should have a main function that tests the function. Example Output: Enter a number: 901 12
2. Stacks and Queues Reinernber: Consider the following function: void systery( int num) { int current: /* create Stack stk and Queue que / Stacks: the function push places the given parameter on the top of the stack, the function pop removes and returns the top of the stack, and the function empty returns true (i.c., 1) if the stack is empty or false (i.e., 0) otherwise. Queues: the function insert places the given parameter on the end of the...