Question

1- Complete all the blanks in the function f1() below such that it implements the operations described in the comments. You may only fill in the blanks and not add or alter other code. Also complete main(). // f1 copies the last *half* of vec's values into a new array pointed to 'arr'. // 'arr' is garbage coming in and must be modified by this function so the // caller can then use the produced array. The values copied from vec Il should then be removed by vec. If there are an odd number of elements in vec, leave the middle element in vec, and let arr have one less element // than vec int f1 vec, int **arr) // { int arrlen = = new int[arrlen); ; i >= _; i--) { for(int i (*arr)[i] vec. back(); vec. } return arrlen; } int main() { vector int> vec1(3); vector<int> vec2(2); = 5; vec1[0] = 3; vec1[1] = 4; vec1[2] vec2[0] = 3; vec2[1] = 4; int *array1, *array2; int ni, n2; n1 = f1(vec1, .); // show how to pass array1 // Should return with vec1 = {3, 4} and array1 = {5}, n1 = 1 n2 = f1(vec2, .); // show how to pass array2 // Should return with vec2 {3} and array2 = {4}, n2 = 1 = // Show cleanup code, if any return; }

Answer 1

CODE:

1 2 #include<iostream> #include<vector> using namespace std; 3 4 5 6 7 8 9 10 11 12 13 14 15 int fl (vector int> <vec, int *arr) Et int arrlen = vec.size()/2; *arr = new int[arrlen]; for(int i = arrlen-1; i >= 0; i--) { (*arr) [i] = vec.back(); vec.pop_back(); } return arrlen; }

int main() = 4; vecl[2] 5; vector int> vecl (3); vector int> vec2 (2); vec1[0] = 3; vec1[1] vec2[0] = 3; vec2[1] 16 17 18 19 20 21 22 23 24 25 int *arrayı, *array2; int ni, n2; nl = fl (veci, Sarrayl); // Should return with war = {3, 4) and arrayı = {5}, nl = 1 26 w w w w w w N N N N N N N N N N 27 28 29 30 31 cont<<"Vector vedl: "; for (int i=0;i<l.size(); i++) Cantec[i]<<" "; 32 cout<<"Value of nl: "<<nl; CRUM "marmaxl: "; for (int i=0;i<nl;i++) Sant <arrayl[i]<<" "; 33 34 35

n2 = fl (vec2, Garray2); // Should return with wel = {3) and arrayl = {4}, n2 = 1 cont<<"Vector vec2: "; for (int i=0;i Wec2.size();i++) Caut<<ec2[i]<<" "; 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 Sout "Value of n2: "<<nl; "mammax.2: "; for (int i=0;i<n;i++) Caut<<array2 [i]<<" "; // Cleanup code delete[] arrayı, array2; veci.clear(); vec2.clear(); return 0; 53 54 55

CODE (for copy):

#include<iostream>
#include<vector>
using namespace std;

int f1(vector<int> &vec, int **arr)
{
int arrlen = vec.size()/2;
*arr = new int[arrlen];
for(int i = arrlen-1; i >= 0; i--){
(*arr)[i] = vec.back();
vec.pop_back();
}
return arrlen;
}

int main()
{
vector<int> vec1(3); vec1[0] = 3; vec1[1] = 4; vec1[2] = 5;
vector<int> vec2(2); vec2[0] = 3; vec2[1] = 4;

int *array1, *array2;
int n1, n2;

n1 = f1(vec1, &array1);
// Should return with vec1 = {3, 4} and array1 = {5}, n1 = 1
/*
cout<<"Vector vec1: ";
for(int i=0;i<vec1.size();i++)
cout<<vec1[i]<<" ";
cout<<endl;
cout<<"Value of n1: "<<n1;
cout<<"\narray1: ";
for(int i=0;i<n1;i++)
cout<<array1[i]<<" ";
*/
  
n2 = f1(vec2, &array2);
// Should return with vec1 = {3} and array1 = {4}, n2 = 1
/*
cout<<"\n\nVector vec2: ";
for(int i=0;i<vec2.size();i++)
cout<<vec2[i]<<" ";
cout<<endl;
cout<<"Value of n2: "<<n1;
cout<<"\narray2: ";
for(int i=0;i<n2;i++)
cout<<array2[i]<<" ";
*/

// Cleanup code
delete[] array1,array2;
vec1.clear();
vec2.clear();
return 0;
}

For output remove the paragraph comments

OUTPUT:

Vector veci: 34 Value of n1: 1 array1: 5 Vector vec2: 3 Value of n2: 1 array2: 4 Process returned © (@xo) Press any key to continue. execution time : 0.121 s

For any doubt please comment.