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An object of mass 0.500 kg is released from the top of a building of height 4.00 m. The object experiences a horizontal const
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Answer #1

Time taken to reach the ground[using second equation of motion ] = sqrt(4/.5*9.81)= 0.9s.

Acceleration is due to gravity =9.81m/s^2 and acceleration in x direction is 2/0.5= 4. So, acceleration in vector form is 4i- 9.8j m/s^2.

Acceleration in x direction is a= 2/0.5= 4. So, Displacement in x direction =0.5*4*0.9^2= 1.62i m and displacement in y direction is -4 m. So, net displacement is 1.62i -4j m.

Net force on both sides must be same. So, product of mass and acceleration must be same. So, mass of harry to hank is 1.22. So the required ratio is 0.82.

If unclear then ask, upvote to appreciate.

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