Question

calculate the generation time (minutes/generation) of 4.9*10^6 CFUs/ml

calculate the generation time (minutes/ generation) of 155*10^8 CFUs/ml

for 3hrs 4.9*10^6

for 6hrs155*10^8

The students UR S pes at diferent times during the growth to do dilution plating and get viable plate counts. Here are the results for the samples taken at hours 3 and 6: 3 hours 10 dilution - too many to count 10"dilution - 476 CFUS 10% dilution - 49 CFUS 10 dilution = 5 CFUS 6 hours 10 dilution = too many to count 10 dilution = 155 CFUS 107 dilution - 17 CFUS 10 dilution - 2 CFUS Which dilution will give the best estimate for the 3 hour time point? Which will give the best estimate at 6 hours? Using these data, how many CFU/ml were present in the original culture at times 3 and 6 hours? (Assume 1 mlinoculum for for each platel HTML Editor BIVA-ALE = B. A V G X 1: X 12pt T - Paragra Best estimate for a 3hr time point would be 10-5 (49 CFU) Best estimate for a 6 time point would be 10-6(155CFU) 4.9-10 CFU/ml for 3hrs 155-10 CFU/ml for 6hrs a es pa

Answer 1

loq (195*10%) = 100 (4.910) 2.303 x 3hrs. 10.196.69 2.30373 - 0.51hr ¥ 30 mins