Question

CMTC Tool shed Slape 4" thik Wolls are bincher wide Foozing race 18 iwekee 3 rows ofrehar in Footing Walls are 8 feet TAI Footings are inches Deep ► duard 01-6"

1- how many rebar on footing? "note 3 rebar on footing"

2-how mach concrete for footing?

3- how mach concrete for footing slab al 4' thicknees?

4- how mach concrete in the wall?

Answer 1

Note - all dimensions are taken from outside to outsde according to short walls long wall method.

Criven are D width of wall a Ginch 2 -1 of footing = 18 inch ③ Height of wall = 8x12=96 inch Depth of footing = 12inches from the figure : - (a) for footing :- (1) length of sideral long wall ) = 240x2=480 inch (2) length of short wall all h) = 168inch (3) front w cell IF) = 72x21 Nos) = 144 inch. (4) Front side wall (f2) = 30x2000)/2 60 inch (5) Inclined wallIf 42.42x2=84.84 inch (6) Front wall (h) - boinches Hence total length of tooting = lithottitf + I + f₂ = 996.84inces total length = 996.84 inches) Hence Ans.(1) Mos of rebar = total length x3 (Qox 12 inches => 996.8483 7 2240 -> (1340s of sticks of rebar Awo

(6) Concrete for footing lengthy width x depth Quantity = 996.848 18x12 duaudy = 215317.44 cubic inches) Ans. (3) concrete for footing slab thickness 4!! duantity a length x Width x depth = 996.848 18X4 Quantidy = 7/772.43 cubi inches) - Ama, o Concrete in the wall = ? for wall :- (4) (bl length of long wall (1) = 222x2 = 444 inches (2) al- l short wall (6) = 168inches (3) front wall (fi) = 48x2 = 96inch (4) front wall (f2) = 42x2 = 84 inch 3) inclined wall (I) = 42.42X2 = 84.84 inches 1 (6) Front wall - Goin Choa. concrete in the wall length x width x height Quantity 936.848 6 ka Quantity & 539619.84 cubic inches Aus Hos o rebar sticks = 13 2 Concrete for footing = 2 15317.44 cubi inches 6 Concrete for footing (41 thick) = 71772.48 cubic inche 9 concrete in wall h 5396 19.84 cubic inches.