Question

1. Use the molecular orbital diagram shown below to determine which of the following molecules/species is most stable (O₂, F₂ and Ne₂) . Explain their magnetic properties using the same diagram. Calculate the bond order in each of the molecule.

Answer 1

Molecular oubital diaguam 0-2P 1 T*2; TT*2px 11 1 1 29 11 W 2P 312P 12p 16 0-2 1 *28 Bond ouder = No - Na 2. electrons in 11 11 25 2S No No. No. of bounding arbitars Na No. of electrons in antibonding orbitale 1L or 2s 10 is => 10 6 =2 2 12 1L Is 12 ris 16 161 11 111 2p 2 022 11 11 Te 2 px 12py 1 11 Trapx 7123 1L 8212 12 x 25 11 25 = No Na 2 10-8 = 1 2 ? 25 11 +25 11 ols 11 11 1s 15 1L aris

11 22 11 11 11 2p 1L 11 Top T*2P, 111 ル ル ap TT 2P7127 => N, - Na -22 2 11/ = 10-10 10 25 0*25 12 25 2 IL 2s - Desnot exist TLF 1L IS 12 is 11 ols since we know that when No) Na moleculle is stable", and when N <Na or No = Na molecule is unstable. there. No > Na in O₂ and Fa molecule ou have positive bond oudere, so they are stable while Ne, has o bond order it does not exist it has a Considering magnetic natele; => in 0, molécule presence of unpaied electrone confirms paramagnetic => there are no unpaired electrons in F, and Ne, so they diamagnetic. nature que