An organic acid has pKa = 8.95. What is its Ka value? Where does the acid fit in Table 16.2?
Table 16.2 Ionization Constants for Some Acids and Their Conjugate Bases at 25°C?

Given : pKa = 8.95
The relationship between the Ka and pKa is given by,
=> Ka = 10-pKa
Hence substituting the values, we get,
=> Ka = 10-8.95 = 1.122 X 10-9 approx.
Since the Ka value of the acid is more than that of boric acid. Hence the acid fits above the boric acid in the periodic table.
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