What is the pKa of an acid that has a Ka value of 7.38 x 10-7?
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a. |
6.13 |
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b. |
7.87 |
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c. |
6.63 |
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d. |
7 |
a) 6.13
pKa = - logKa
Given
Ka = 7.38 x 10-7
pKa = - log [ 7.38 x 10-7]
pKa = 7 - log 7.38 = 7- 0.868 = 6.13
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