![we know, force acting on a wire A in a magnetic field is I I (di x die length of wire] B = magnetic field] so force on side B](http://img.homeworklib.com/questions/a302d680-5781-11ec-9c97-49a0392794dd.png?x-oss-process=image/resize,w_560)

7 Figure 3 (b) A conducting rectangular loop of wires whose sides are a and b...
A rectangular loop (area = 0.250 m2) turns in a uniform magnetic field with B = 0.210 T. At an instant when the angle between the magnetic field and the normal to the plane of the loop is π/2 rads and increasing at the rate of 0.530 rad/s, what is the magnitude of the emf induced in the loop? 9.91E–2 V 1.47E–2 V 2.78E–2 V 5.25E–2 V 0
В 1 DU! Up B=0 Down In the figure provided, a rectangular loop of copper wire is perpendicular to a 2.40 T magnetic field and half in and half out the field. The loop has dimensions 6.40 m for the horizontal wires, and 5.00 m for the vertical wires. What is the magnetic flux through the loop. 38.4 T m2 OOT m2 154 T m2 76.8 T m2
working with answers will be great
3. (60pts) A rectangular, conducting, wire loop of sides L and W, total mass m, and total resistance R initially lies in the horizontal ry-plane, with corners at (x, y, z) = (0,0,0), (0,W.0), (L,0,0), and (L, W.0). There is a uniform, upward magnetic field B = Bk in the space within and around the loop. The side of the loop that extends from (0,0,0) to (L,0,0) is held in place on the x-axis;...
A conducting rod spans a gap of length L = 0.315 m and acts as the fourth side of a rectangular conducting loop, as shown in the figure. A constant magnetic field B = 0.45 T pointing into the paper is in the region. The rod is moving under an external force with an acceleration a= At2, where A = 6.5 m/s4. The resistance in the wire is R= 110ΩPart (a) Express the magnitude of the magnetic flux going through...
A rectangular conducting loop is being pulled at constant speed v=4.00 m/s from a region of uniform magnetic field by a constant external force F. The dimentions of the loop are w=.3 m, l=.9 m, and has a resistance of R=5 ohms. In the region where the magnetic field is nonzero, it is directed out of the page and has magnitude of 3.00 T. External force is to the right, magnetic field is pointing out of the page, and velocity...
Part of a single rectangular loop of wire with dimensions shown in the figure (Figure 1) is situated inside a region of uniform magnetic field of 0.336 T . The total resistance of the loop is 0.532 Ω . Calculate the force required to pull the loop from the field (to the right) at a constant velocity of 1.59 m/s . Neglect gravity.
A rectangular loop of wire with dimensions 2.43 cm by 8.38 cm and resistance 0.593 Ω is being pulled to the right out of a region of uniform magnetic field. The magnetic field has magnitude 3.01 T and is directed into the plane of the following figure(Figure 1). Part A At the instant when the speed of the loop is 3.09 m/s and it is still partially in the field region, what is the magnitude of the force the magnetic field exert...
(BEKP 2453) QUESTION 2 Figure Q2 (a) shows a rectangular conducting loop is lies on a uniform magnetic field of B RBo. The loop is allowed to pivot on centre of arm 2 and 4. Derive the force equation on arm 1 and 3. ) (7 marks) in Prove that the torque of the loop is not influence by force develop on arm 2 and 4. (6 marks) i What is the general torque equation for the rectangular loop? (3...
A rectangular loop rotates with a constant angular velocity
about an axis as shown. It makes one complete rotation in 0.03 s.
The magnetic field lines are straight and parallel as shown. They
are perpendicular to the axis of rotation. The lengths are c= 0.5 m
and d= 3.5 m, the strength of the magnetic field is 0.08 T. The
total resistance of the loop is 174 ?.
1. What is the magnetic flux through the loop at the instant...
Part of a single rectangular loop of wire with dimensions shown in the (Figure 1) is situated inside a region of uniform magnetic field of 0.740 T . The total resistance of the loop is 0.780 Ω . Calculate the force required to pull the loop from the field (to the right) at a constant velocity of 5.20 m/s . Neglect gravity.