Question

The diagram below shows a circuit consisting of a resistance R = 125 ohm, an inductor with L = 71.0 mH and internal resistance r= 48 ohm, and a capacitor C = 0.203 muF. The circuit is being driven at 968 Hz and carries an rms current of 46.2 mA.What is the rms voltage between a and b, that is, across R? What is the rms voltage between b and e, that is, across the inductor? What is the rms voltage between e and d, that is, across C? What is the rms voltage supplied by the generator? What is the power factor for this circuit?

Answer 1

R= 125Ω L=71.0m H internal resistance(r)-48Ω al-_ R+r 125 +48 = 173Ω reactance-J173, +378.1 0-41 5.79Ω =968 x 2x π x 71 x 10-3 610x) = 378·10Ω oc 2π x 968 x 0203 x 10" current-46.2mA V=IR V= 46.2×10-3×415·79Ω V=19.20V rms voltage across the bc V- ((al)2+72x1-1968 x 2 x π x 71x10-3)2+482 x(46.2x10-3)-957.62V V(generator)Iimpedence