Question

9.2.- Find the son of the regression line for the given date. The constate of the date and the regionin (The pair of what colon) Then there we pred the value of your each of the given values in the below shows the heights into and the number of res of intings at Height 518 x*830 let 37 315 735 Find the regression Round the wope to the decimal places as needed. Round they need to two decimal places as needed

Answer 1

solution:

The regression equation is

ŷ = 0.04395X + 18.57085

explaination:

X Values 772 628 518 506 496 483 Y Values 51 48 46 43 37 36 51 - M: 43.5 Y-Dependent 46 M: 567.1667 41 36 + 480 560 640 720 800 X - Independent Regression Line (j = 0.04X + 18,57) Estimate Calculation Summary Sum of X = 3403 Sum of Y = 261 Mean X = 567.1667 Mean Y = 43.5 Sum of squares (SSy) = 63964.8333 Sum of products (SP) = 2811.5 Regression Equation = û = bx + a b = SPISSx = 2811.5763964.83 = 0.04395 a = My - bMx = 43.5 - (0.04*567.17) = 18.57085 ŷ = 0.04395X + 18.57085 Y- My X - Mx 204.8333 60.8333 -49.1667 -61.1667 - 71.1667 -84.1667 7.5 4.5 2.5 -0.5 -6.5 -7.5 (X - Mx)2 41956.6944 3700.6944 2417.3611 3741.3611 5064.6944 7084.0278 (X - MX)(Y - My) 1536.25 273.75 -122.9167 30.5833 462.5833 631.25 SS: 63964.8333 SP: 2811.5

1) At x=500 the pridiction value is

ŷ = 0.04395*500+ 18.57085=40.5458

y=40.5458

2)at x=639 the pridiction value is

ŷ = 0.04395*639 + 18.57085=46.5230

Y^=46.5230.

3) at x= 315 the pridiction values

ŷ = 0.04395*315+ 18.57085=32.4151

y^=32.4151

4) at x= 735 the pridiction values

ŷ = 0.04395*735 + 18.57085=50.8741

Y^= 50.8741