
4.15 A PN diode with lengths much larger than the carrier diffusion length such as shown...
solid state electronic devices ch5 pro22
In a simple p-n diode, if the diffusion coefficent for holes is twice than that for the electrons, the minority carrier concentration at n side is twice than that in p side, and the diffusion coefficent for holes is also twice of that for the electrons, calculate the injection efficiency for this diode at x, = 0.
Problem 4: Narrow-Base Diode Consider an ideal pn* step-junction Si diode maintained at 300K with cross-sectional area A = 104cm2. The doping concentration on the p-type side is Na= 1017 cm3 (uncompensated). (The n-type side is degenerately doped.) The electron recombination lifetime in the p-type region is tn = 10-6 s. The width of the quasi-neutral p-type region is 1 um, for VA=0 V. a Is this a narrow-base diode? Justify your answer. b) Calculate the diode saturation current Io....
A Si PN junction diode has constant doping at both sides, Na and Nd in P and N side, respectively. The width of the P side is W and the width of the N side is L: W << Le and L >> Lh. Le and Lh are the minority carrier diffusion length in each side. The lifetime of both minority carriers is τ. Assume the contacts at both ends of the PN junction are Omic contact. The PN junction...
3.13 Si pn junction Consider a long pn junction diode with an acceptor doping Naof 1018 cm-3 on the p-side and donor concentration of Nj on the n-side. The diode is forward biased and has a voltage of 0.6 V across it. The diode cross-sectional area is 1 mm2. The minority carrier recombination time, T, depends on the total dopant concentration, Ndopant (cm), through the following approximate empirical relation (5x 10-7)/(1 + 2 10-17N1°pan.) where T is in seconds. (a)...
3.13 Si pn junction Consider a long pn junction diode with an acceptor doping Naof 1018 cm-3 on the p-side and donor concentration of Nj on the n-side. The diode is forward biased and has a voltage of 0.6 V across it. The diode cross-sectional area is 1 mm2. The minority carrier recombination time, T, depends on the total dopant concentration, Ndopant (cm), through the following approximate empirical relation (5x 10-7)/(1 + 2 10-17N1°pan.) where T is in seconds. (a)...
Problem 4 (25 points) Consider a silicon pn junction at T-300 K, N,-1x1017 ст?, ND-11016 Cm -, The minority carrier lifetimes are τ u-^ 1 μs and τ p-1 μs. The minority carrier diffusion coefficients are Da-25 cm2/s, DR-10 cm2/s. n1-1.5x1010 cm -3 kT - 0.026V Low-level injection is defined to be when the minority carrier concentration at the edge of the space charge region becomes equal to one-tenth the majority carrier concentration. Determine the value of the voltage across...
Problem 4 (25 points) Consider a silicon pn junction at T-300 K, NA-ND- 1x101° cm3. The minority carrier lifetimes are τ n-0.01 μs and τ p-0.01 us. The junction is forwardbiased with Va 0.6V. The minority carrier diffusion coefficients are Dn-20 cm s, Dp 10 cm Is. n.-1.5x 1010 cm-3 Depletion region n-type p-type a) (10 points) Calculate the excess electron concentration as a function of x in the p side (see the figure above). b) (5 points) Calculate the...
A pn junction diode is made of a new semiconductor with 10^16cm-3 donors in the n side and 2x10^17cm-3 acceptors on the p-side. Intrinsic carrier concentration is same as silicon 10^10cm-3at room temperature. Let's assume that a forward bias voltage is applied in a way that it create following minority carrier concentrations in quasi neutral regions. p(x) =10^4 + 10^14/[1+10^4(x-xn)] (cm-3) where x>xn>0 and n(x) = 500-10^15/[10^4(x+xp)-1] (cm-3) where x<-xp<0. x is given in cm scale. Calculate the total current...
A pn junction diode is made of a new semiconductor with 10^16cm-3 acceptors in the p side and 2x10^17cm-3 donors on the n-side. Intrinsic carrier concentration is same as silicon 10^10cm-3 at room temperature. Let's assume that a forward bias voltage is applied in a way that it create following minority carrier concentrations in quasi neutral regions. n(x) =10^4 - 10^14/[10^4(x+xp)-1] (cm-3) where x<xp<0 and p(x) = 500+10^15/[10^4(x+xn)+1] (cm-3) where x>xn>0. x is given in cm scale. Calculate the total...
An important application of PN diodes is their use as photodetectors. The optical radiation creates electron-hole pairs in the depletion region and regions within the diffusion lengths near the depletion edges. These e-h pairs are collected as a photocurrent. The e-h pairs are generated at the rate GL 1022 cm-3s1. Calculate the photocurrent. Consider a silicon PN diode at 300K with following parameters Equation for photocurrent calculation: AGL (W Ln Lp) A 104 um2 Na = 2 x 1016 cm-3...