HomeworkLib
Question

help pls

SORU-7 In a series RLC circuit R = 1000. When the capacitor is removed (RL), the current lags behind the voltage by radian. W

engineering   Electrical-Engineering   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

1002 L. oma am 7 . Z Z = R+ 1 *L-XL) c is removed when Z z RtjXL When L is removed Zz R+Cjx) tano Xe 2 tan oz -0 XL R R.from of = Xc X2 R XL-XL Z z R+ 1 CXL-Xe) ZER+10) ZER z = 1002

0 0
Add a comment
Know the answer?
Add Answer to:
help pls SORU-7 In a series RLC circuit R = 1000. When the capacitor is removed...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • RLC frequency limits Last week you studied the driven RC circuit and the driven RL circuit....

    RLC frequency limits Last week you studied the driven RC circuit and the driven RL circuit. Consider the driven series RLC circuit. Its impedance is Z=R+j(ωL−1/(ωC)) . (a) For very high frequencies the driven RLC circuit behaves like an RL circuit (the effect of the capacitor becomes negligible). In this case does the current lead or lag the applied voltage in phase? A. lags B. leads C. neither What value in degrees does |ϕ| approach as ω→∞ ? (b) For...

  • We have a series RLC circuit with an AC voltage source: The resistance is 100Ohm, the inductance ...

    We have a series RLC circuit with an AC voltage source: The resistance is 100Ohm, the inductance is 10mH, the capacitance is 10mF. Select all the right answers. At 60Hz What is true? Question 10 options: The current through the inductor is larger than through the resistor The voltage across the inductor is larger than the voltage across the capacitor The voltage is lagging behind the current at the source The voltage and the current are in phase at the...

  • Saved We have a series RLC circuit with an AC voltage source: The resistance is 100Ohm,...

    Saved We have a series RLC circuit with an AC voltage source: The resistance is 100Ohm, the inductance is 10mH, the capacitance is 10mF. Select all the right answers. At 60Hz the total impedance is Question 13 options: less than 100Ohm Is more than 100Ohm Is within 1% of 100 Ohm Is not within 1% of 100Ohm Question 14 (1 point) Saved We have a series RLC circuit with an AC voltage source: The resistance is 100Ohm, the inductance is...

  • Function Generatr Inductor Model Ra R, Figure 1 Series RLC Circuit Preliminary This laboratory wi...

    Function Generatr Inductor Model Ra R, Figure 1 Series RLC Circuit Preliminary This laboratory will demonstrate how varying resistance changes the natural response of a series RLC circuit (Fig. 1). The function generator is modeled as an ideal voltage source v(t) 5 u() V in series with source resistance Rs-50Q. After measurements using an LCR meter, the inductor is modeled as an ideal L 90 mH inductor in series with resistance RL-20Q. The capacitance is C-0.22 μF. 1) Calculate the...

  • a series RLC circuit contains a 148 ohm resistor, a 1.50uF capacitor, and a 35.7mH inductor....

    a series RLC circuit contains a 148 ohm resistor, a 1.50uF capacitor, and a 35.7mH inductor. The generator has a frequency of 512Hz and a rms voltage of 35V. Determine the peak current in the circuit.

  • A series RLC circuit has a capacitor with a capacitance of 36.0 μF , an inductor...

    A series RLC circuit has a capacitor with a capacitance of 36.0 μF , an inductor with an inductance of 0.700 H and a resistor with a resistance of 143 Ω. The circuit is attached to a source that has a rms voltage of 65.0 V and a frequency of 91.0 Hz. What is the peak current?

  • A resistor (R = 9.00 x 102.2), a capacitor (C = 0.250 uF), and an inductor...

    A resistor (R = 9.00 x 102.2), a capacitor (C = 0.250 uF), and an inductor (L = 1.70 H) are connected in series across a 2.40 x 102-Hz AC source for which AVmax = 1.50 x 102 V. (a) Calculate the impedance of the circuit. Ο ΚΩ (b) Calculate the maximum current delivered by the source. (c) Calculate the phase angle between the current and voltage. (d) is the current leading or lagging behind the voltage? The current leads...

  • A parallel plate capacitor is used in a series RLC circuit along with a 0.650-H inductor....

    A parallel plate capacitor is used in a series RLC circuit along with a 0.650-H inductor. When the space between the plates is filled with a dielectric with κ = 5.57, the resonant frequency is 220 Hz. Now the dielectric is removed, leaving air between the capacitor plates. What is the new resonant frequency?

  • A series RLC circuit has a capacitor with a capacitance of 31.0 μF , an inductor...

    A series RLC circuit has a capacitor with a capacitance of 31.0 μF , an inductor with an inductance of 0.600 H and a resistor with a resistance of 88.0 Ω. The circuit has a rms current of 9.00 A when the frequency is 71.0 Hz. What is εrms?

  • A series RLC circuit has a capacitor with a capacitance of 19.0 μF , an inductor...

    A series RLC circuit has a capacitor with a capacitance of 19.0 μF , an inductor with an inductance of 1.40 H and a resistor with a resistance of 58.0 Ω. The circuit has a rms current of 5.60 A when the frequency is 95.0 Hz. What is the phase angle?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT