Question

Predict the effect of decreasing the volume of the container for each equilibrium and why.

a.) 2H₂O (g) + N₂ (g) <--> 2H₂ (g) + 2NO (g)

b.) SiO₂ (s) + 4HF (g) <--> SiF₄ (g) + 2H₂O

c.) CO (g) +H₂ (g) <--> C (s) + H₂O (g)

Answer 1

a.) 2H₂O (g) + N₂ (g) <--> 2H₂ (g) + 2NO (g)

decrease in volume shifts the equilibrium position towards that the side which has less number of moles of gas

here , in this equation :

reaction shifts left side because number of moles gases are less .

so

forms more of H2O and N2

and less H2 and NO

b.)

SiO₂ (s) + 4HF (g) <--> SiF₄ (g) + 2H₂O (l)

here equilibrium shifts right side. so

forms more SiF4 and H2O , less SiO2 and HF

c.)

CO (g) +H₂ (g) <--> C (s) + H₂O (g)

here equilibrium shifts right side.

forms more C and H2O , less CO and H2