

SOLUTION :
Ix = bh^3 / 12 = 15262.61 mm^4
Iy = hb^3 / 12 = 10961.98 mm^4
So,
b^2 Ix = b^3 h^3 / 12 = b^2 * 15262.61
Iy = b^3 h /12 = 10961.98
So,
b^2 Ix / Iy = h^2 = b^2 * (15262.61 / 10961.(8)
=> h = b sqrt (15262.61 / 10961.98)
=> b = h / 1.18
So,
Ix = (h/1.18) * h^3 /12= 15262.61
=> h = (15262.61 * 1.18 * 12 )^(1/4)
=> h = 21.56 mm (ANSWER).
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