Question

x1	6	11	15	18	20
y1	6	8	12	20	30

Compute b1 and b0 (to 3 decimals). Enter negative values as negative numbers.

b1

b0

Complete the estimated regression equation (to 3 decimals). Enter negative values as negative numbers.

y^ = ____ + _____ x

x1

x2

x3

x4

x5

Compute the standardized residuals. Enter negative values as negative numbers.

	standardized residual
1	(to 4 decimal places)
2	(to 4 decimal places)
3	(to 4 decimal places)
4	(to 4 decimal places)
5	(to 4 decimal places)

Answer 1

Line of Regression Y on X i.e Y = bo + b1 X
					X	Y	(Xi - Mean)^2	(Yi - Mean)^2	(Xi-Mean)*(Yi-Mean)
6	6	64	84.64	73.6
11	8	9	51.84	21.6
15	12	1	10.24	-3.2
18	20	16	23.04	19.2
20	30	36	219.04	88.8

calculation procedure for regression
mean of X = sum ( X / n ) = 14
mean of Y = sum ( Y / n ) = 15.2
sum ( (Xi - Mean)^2 ) = 126
sum ( (Yi - Mean)^2 ) = 388.8
sum ( (Xi-Mean)*(Yi-Mean) ) = 200
b1 = sum ( (Xi-Mean)*(Yi-Mean) ) / sum ( (Xi - Mean)^2 )
= 200 / 126
= 1.587
bo = sum ( Y / n ) - b1 * sum ( X / n )
bo = 15.2 - 1.587*14 = -7.022
value of regression equation is, Y = bo + b1 X
Y'=-7.022+1.587* X          
------------------------------------------------------------------------------
b1 = 1.587 ;
bo = -7.022
regression equation = Y'=-7.022+1.587* X      

RESIDUAL CHART

Observation	Y	Predicted	Residual
1	6.0	2.5	3.5
2	8.0	10.4	-2.4
3	12.0	16.8	-4.8
4	20.0	21.5	-1.5
5	30.0	24.7	5.3