Question

Can you make this a function? Thank you.

int locationOfMin(const string a[], int n): Return the position of a string in the array such that that string is < = every string in the array. If there is more than one such string, return the smallest position of such a string. Return -1 if the array has no elements. Here's an example: string people[5] = { "samwell", "jon", "margaery", "daenerys" "tyrion" }: int j = locationOfMin(people, 5);//returns 3, since daenerys is earliest //in alphabetic order

Answer 1

This is the function which is desired. It might be required to change a little based on how it is being called and used, so modify accordingly for accurate result.

static int locofMin(String[] a, int posi)
{
int pos=0;
String temp;
String[] arr1=a;
String[] arr2=a;

if(posi==0)
{
pos=posi;
  
}
else
{
for(int i=0;i<posi-1;i++)
{
for(int j=i+1;j<posi;j++)
{
if (arr1[i].compareTo(arr1[j])>0)
{
temp = arr1[i];
arr1[i] = arr1[j];
arr1[j] = temp;
}
}
}
  
for(int ak=0;ak<posi;ak++)
{
System.out.println("arr1 :"+arr1[ak]);
System.out.println("arr2 :"+arr2[ak]);
}
  
for(int i1=0;i1<posi-1;i1++)
{
for(int k1=0;k1<posi;k1++)
{
if(arr1[i1].equals( arr2[k1] ))
{
pos=k1;
System.out.println("arr1[i1] "+arr1[i1]+" arr2[k1]"+arr2[k1]);
break;
}
}
}
}

return pos;
}