Question

B) The previous problem is modified in that the plate struck by the ball now has a mass equal to that of the ball and is supported as shown. Compute thoe final velocities of both masses immediately after impact if the plate is initially stationary and all other conditions are the same as stated in the pre- vious problem to

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Answer 1

t - momentum conserved Ball = m_1 v_1t = m_1 v_1t^1 v_1t^1 = v_1t = 24 cos 60 degrees = 12 m/sec plate: - m_2 v_2t = m_2 v_2t^1 v_2t^1 = v_2t = 0 n - momentum m_1 v_1n + m_2 v_2n = m_1 v_1n^1 + m_2 v_2n^1 -24 sin 60 degree = v_1n^1 + v_2n^1 Restitution (e) e = v_2n^1 - v_1n^1/v_1n - v_2n 0.8 = v_2n^1 - v_1n^1/-24 sin 60 degree By solving v_1n^1 = -2.08 m/sec v_2n^1 = -18.71 m/sec v_1^1 = squareroot (v_1t)^2 + (v_1n^1)^2 = 12.20 m/sec Now, theta = tan^-1 (v_1n^1/v_1t^1) = -9.83 degree