Question

Exercise 3: Write a program that reads a file and prints the letters in decreasing order of frequency. Your program should convert all the input to lower case and only count the letters a-z. Your program should not count spaces, digits, punctuation, or anything other than the letters a-z. Find text samples from several different languages and see how letter frequency varies between languages. Compare your results with the tables at https://wikipedia.org/wiki/Letter_frequencies.

PYTHON PLEASE the text can be found here :  www.py4e.com/code3/mbox-short.txt on here!! thank you so much

Enter file name: mbox-short.txt 0.09290243193820177 e 0.08926221523422145 a 0.07680344538820433 i 0.0713345752226001 O 0.0694546511031 7366 r 0.06921538803342847 t 0.06388323962196435 s 0.05337275477244373 u 0.052774597098080765 C 0.04400731461384649 n 0.04267427751098046 p 0.041631 77413566216 m 0.03424879941209646 d 0.03130928169808419 | 0.023789585220378377 h 0.021 482405619264094 f 0.019944285885187908 K 0.01938030864935997 b 0.01755165518773606 9 0.01 7038948609710662 v 0.01638952027754516 j 0.01098901098901099 y 0.010014868490762736 w 0.008237485686941364 x 0.0013330371028660297 z 0.0009741424982482526 9

it should be in percentage if that is possible!

THANK YOU

Answer 1

Given below is the code for the question. PLEASE MAKE SURE INDENTATION IS EXACTLY AS SHOWN IN IMAGE.
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filename = input('Enter file name: ')
f = open(filename, 'r')
frequencies = {}
totalLetters = 0
for line in f.readlines():
   line = line.lower()
   for c in line:
       if c.isalpha():
           totalLetters += 1
           if c in frequencies: #letter is already in dictionary
               frequencies[c] += 1
           else: #letter not yet in dictionary
               frequencies[c] = 1
f.close()
#now make a list of tuples with (freq, char) and then sort on decreasing frequency
freqlist = []
for c in frequencies:
   freqlist.append((frequencies[c], c))

freqlist.sort(reverse = True)
#now print the sorted results

for t in freqlist:
   occurs = t[0]
   letter = t[1]
   percent = occurs / totalLetters
   print('{} {} \t {}%'.format(letter, percent, round(percent * 100, 2)))

Enter file name: short.txt e 0.09290243193820177 9.29% a 0.08926221523422145 8.93% i 0.07680344538820433 7.68% 0 0.0713345752226001 7.13% r 0.06945465110317366 6.95% t 0.06921538803342847 6.92% s 0.06388323962196435 6.39% u 0.05337275477244373 5.34% C 0.052774597098080765 5.28% n 0.04400731461384649 4.4% p 0.04267427751098046 4.27% m 0.04163177413566216 4.16% d 0.03424879941209646 3.42% 1 0.03130928169808419 3.13% h 0.023789585220378377 2.38% f 0.021482405619264094 2.15% k 0.019944285885187908 1.99% b 0.01938030864935997 1.94% g 0.01755165518773606 1.76% v 0.017038948609710662 1.7% j 0.01638952027754516 1.64% y 0.01098901098901099 1.1% w 0.010014868490762736 1.0% x 0.008237485686941364 0.82% z 0.0013330371028660297 q 0.0009741424982482526 0.13% 0.1%

1 2 3 4 5 로 6 7 00 > 8 9 filename = input('Enter.file name: ') f = open(filename, 'r') frequencies = { } totalLetters = 0 for line in f.readlines(): line = line.lower() for c.in line: if c.isalpha(): totalLetters += 1 if c in frequencies: #letter is already in dictionary frequencies[C] += 1 else: #letter:not yet.in dictionary frequencies[C] := 1 f.close( #now make a list of tuples with (freq, char) and then sort on decreasing frequency freqlist [] for c in frequencies: freqlist.append((frequencies[c], c)) D-LO 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 freqlist.sort (reverse = True) #now print the sorted results F for t in freqlist: occurs = t[O] letter - t[1] percent = occurs / totalLetters print('{}{} \t.{}}'.format(letter, percent, 'round (percent *. 100, 2)))