Question

Write a Python program stored in a file q6.py that takes a text
(without punctuation) as input and prints the number of occurrences of each word.
Your program is case-insensitive, meaning that uppercase and lowercase of the same
letter is considered the same. Printing should be done in decreasing order of the number
of occurrences. If several words have the same number of occurrences, they should be
printed in alphabetical order. A new line must be printed between the words that have
different number of appearances.
Use a Python dictionary to store the letters and the count of letters.

ex:

Enter text : You cannot end a sentence with because because
because is a conjunction

Word Statistics :
because appeared 3 times .

a appeared 2 times .

cannot appeared 1 times .
conjunction appeared 1 times .
end appeared 1 times .
is appeared 1 times .
sentence appeared 1 times .
with appeared 1 times .
you appeared 1 times

Answer 1

Below is the complete code as per the requirements. It is well explained inside the code using comments.

# read text
text = input('Enter text: ')

# split the words
words = text.split()

# create a dictinary
freq = {}

# loop through all words
for word in words:
    word = word.lower()
    # if word exists in dictionary
    # increment the value by 1
    if word in freq:
        freq[word] += 1
    # otherwise initialize the value by 1
    else:
        freq[word] = 1

# sort the words in decreasing value
sorted_words = sorted(freq, key=freq.get, reverse=True)

count = freq[sorted_words[0]]
# print the word statistics
print('Word Statistics :')
for word in sorted_words:
    # check for new line
    if count != freq[word]:
        print()
    print(word, 'appeared', freq[word], 'times.')
    count = freq[word]

Below is the screenshot of code:

Below is the sample output:

This completes the requirement. Let me know if you have any queries.

Thanks!