Question

Consider the following C++ program: #include <iostream> #include <cstdlib> using namespace std; int main int n =0; int i = 0; cout << "Please enter a strictly positive number:"; cin >> n if (n <= 0) exit(EXIT_FAILURE) while (n > 1) n-n/2; i << endl; cout"Output:" return 0; Answer the following questions: What is the output of the program for each of the following values of n: -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9? What does the program do? Write a general statement that captures the computation being performed by the program. I. 2.

Answer 1

Answer 1:

Output for value of n are mentioned below

-1 => None

0 => None

1 => 0

2 => 1

3 => 1

4 => 2

5 => 2

6 => 2

7 => 2

8 => 3

9 => 3

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Answer 2:

This program basically counts the number of iteration until a division of user input value by 2 is greater than 1. If user input value is less than or equal to 0 then program exit without any error.

This program will first initialize two integer variables i and n as value zero.

Then program will ask to enter positive integer.

If user enters value which is less than or equal to 0 then the program exits without any error.

After that program counts the number of iteration until a division of user input value by 2 is greater than 1. For example if user enters 9 then program sets 9 into variable n.

In while loop it satisfies the condition and iterates for 3 times until the division of n became 1 so after 3rd iteration while loop condition failed to satisfy so loop terminates.

Then program prints the result of i as 3.