#include <iostream>
using namespace std;
int main()
{
int i,n;
int counter=0;
cin >> n;
for (i = 1; i <= n; i++)
{
if (n % i == 0 )
{
counter++;
}
/*else
{
counter++;
i++;
}*/
}
if (counter == 2)
cout << n << " is a
prime number with only 2 factors ( " << n << " and "
<< 1 << " )." << endl;
else
cout << n << " is not
prime. It has more than 2. (" << 1 << " & "
<<i<<","<< counter <<")"<<
endl;
return 0;
}
How do you modify this code for non-prime number.
For example, if the input is 4, I want it to display "4 is not a prime because it has more than 2 factors. (1,2,4).
If you have any doubts please comment below. Please give upvote if you like this.
Cpp Code:
#include <bits/stdc++.h>
using namespace std;
int main()
{
int i,n;
int counter=0;
cin >> n;
for (i = 1; i <= n; i++)
{
if (n % i == 0 )
{
counter++;
}
}
if (counter == 2)
cout << n << " is a prime number with only 2 factors (
" << n << " and " << 1 << " )." <<
endl;
else
{
cout << n << " is
not prime. It has more than 2. (";
// loop for printing factors
of n if n is non-prime
for(int i=1;i<n;i++)
{
if(n%i==0)
// condition for factor
cout << i<<","; //display the factors
}
cout<<n<<")"<<
endl;
}
return 0;
}


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