Using Java, how would you test if a int number contains the digit 8 using recursive functions?
public static boolean isLucky(int number)
Here is the answer for your question in Java Programming Language.
CODE :
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import java.util.*; import java.io.*; public class Main { public static void main(String[] args) { //Prompting user for input System.out.println("Please enter an integer"); Scanner s = new Scanner(System.in); int number = s.nextInt(); //Calling isLucky method with the user input as parameter boolean result = isLucky(number); //If the method returns true the number contains 8 if(result == true) { System.out.println("Lucky number"); } else //Else the number doesnot contain 8 { System.out.println("Not a Lucky number"); } } //Implementing isLucky() method public static boolean isLucky(int number) { //Variables to hold user input and each digit to check for 8 int n = number,rem; while(n>0) //Loop iterates through all the digits of the number { //Returns last digit as remainder rem = n%10; //Returns the number removing last digit n = n/10; if(rem!=8) //If the remainder does not contain digit 8 { return isLucky(n); //Recursively calling the same function } else if(rem == 8) { return true ; // Else returns true } } return false; //If there is no digit 8 in number returns false } } |
SCREENSHOTS:
Please see the screenshots of the code below for indentations of the code.


OUTPUT:


Any doubts regarding this can be explained with pleasure:)
Using Java, how would you test if a int number contains the digit 8 using recursive...
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