


|
Subnet Name |
Needed Size |
Allocated Size |
Address |
Mask |
Dec Mask |
Assignable Range |
Broadcast |
|
Lan-05 |
290 |
510 |
183.14.0.0 |
/23 |
255.255.254.0 |
183.14.0.1 - 183.14.1.254 |
183.14.1.255 |
|
Lan-02 |
260 |
510 |
183.14.2.0 |
/23 |
255.255.254.0 |
183.14.2.1 - 183.14.3.254 |
183.14.3.255 |
|
Lan-04 |
175 |
254 |
183.14.4.0 |
/24 |
255.255.255.0 |
183.14.4.1 - 183.14.4.254 |
183.14.4.255 |
|
Lan-03 |
130 |
254 |
183.14.5.0 |
/24 |
255.255.255.0 |
183.14.5.1 - 183.14.5.254 |
183.14.5.255 |
|
Lan-01 |
100 |
126 |
183.14.6.0 |
/25 |
255.255.255.128 |
183.14.6.1 - 183.14.6.126 |
183.14.6.127 |
|
Lan-06 |
100 |
126 |
183.14.6.128 |
/25 |
255.255.255.128 |
183.14.6.129 - 183.14.6.254 |
183.14.6.255 |
|
Router 0 |
2 |
2 |
183.14.7.0 |
/30 |
255.255.255.252 |
183.14.7.1 - 183.14.7.2 |
183.14.7.3 |
|
Router 1 |
2 |
2 |
183.14.7.4 |
/30 |
255.255.255.252 |
183.14.7.5 - 183.14.7.6 |
183.14.7.7 |
|
Router 2 |
2 |
2 |
183.14.7.8 |
/30 |
255.255.255.252 |
183.14.7.9 - 183.14.7.10 |
183.14.7.11 |
| Router 3 | 2 | 2 | 183.14.7.12 | /30 | 255.255.255.252 | 183.14.7.13 - 183.14.7.14 | 183.14.7.15 |
Answer A
**************
126 hosts
Answer B
**************
510 hosts
Answer C
**************
254 hosts
Answer D
**************
254 hosts
Answer E
**************
510 hosts
Answer F
**************
126 hosts
Answer G
**************
2 Ips connection between router 0 and 1 1 and 2
if you have any doubt then please ask me without any hesitation in
the comment section below , if you like my answer then please
thumbs up for the answer , before giving thumbs down please discuss
the question it may possible that we may understand the question
different way and i can edit and change the answers if you argue,
thanks :)
please help me complete this exam, i've work 12 hours per day, doing the 2nd/Grave yard...
Given an IP address and mask of 192.168.0.0 /24 (address / mask), design an IP addressing scheme that satisfies the following requirements. Network address/mask and the number of hosts for Subnets A and B will be provided by your instructor. Subnet Number of Hosts Subnet A 25 Subnet B 75 The 0th subnet is used. No subnet calculators may be used. All work must be shown on the other side of this page. Subnet A Specification Student Input Points Number...
Task 1: Design a Logical LAN Topology Step 1: Design an IP addressing scheme Given the IP address block of 192.168.7.0 /24, design an IP addressing scheme that satisfies the following requirements Subnet Subnet A Subnet B Number of Hosts 110 54 The 0 subnet is used. No subnet calculators may be used. Create the smallest possible subnets that satisfy the requirements for hosts. Assign the first usable subnet to Subnet A. Subnet A Specification Student Input Number of bits...
A/ Given the following IP address from the Class B address range using the default subnet mask: 100.110.0.0. Your network plan requires no more than 64 hosts on a subnet. When you configure the IP address in Cisco IOS software, which value should you use as the subnet mask? 255.255.0.0 255.255.128.0 255.255.255.128 255.255.255.252 B/ Identify how many valid host addresses can you have on 192.168.27.32 network with a subnet mask of 255.255.255.240. (2^4) - 2 (2^3) – 2 (2^2)...
using the information given below
. what is the ip address , subnet mask , default gateway?
** corrections
# of bits in subnet for A
:6
# of bits in submet for B:
3
PC-A
R1 G0/0
R GO/1
S1
PC-B ?
assign the IP ADDRESS information with given information
Given, IP address: 202.44.66.0/24 For Subnet A: It needs 2 valid hosts 2 valid hosts + 2 (network and broadcast) = 22 i.e., It needs 2 bit as host...
Consider a network with network address 192.168.10.0/24, divide this network into 6 equal size subnets. And find followings Subnet mask Size of a subnet Network addresses of each subnet Broadcast addresses of each subnet First 2 IP addresses of each subnetwork. Answer following questions based on thee values given below Number of needed usable hosts in a single sub net - 22 Network Address - 201.168.75.0 Address class Default mask subnet mask Number of bits borrowed Total number of subnets...
Network IP Addressing Network Layout of 2 networks Given an IP address and mask of 172.23.29.0/24, design an IP addressing scheme that satisfies the following requirements. Subnet B Specification This network requires space for 62 machines plus the router Number of bits in the subnet Blank 1 IP mask (binary) Blank 2 New IP mask (decimal) Blank 3 Maximum number of usable subnets of this size when using this mask (including the 0th subnet) Blank 4 Number of usable hosts...
In a class B subnet, we know the IP address of one of the hosts and the subnet mask as given below: IP Address: 188.48.82.176 Subnet mask: 255.255.255.248 1) What is the first valid host address in the subnet? (in dotted decimal) 2) What is the last valid address in the subnet? (in dotted decimal) 3) What is the subnet network address? (in dotted decimal) 4) What is the subnet broadcast address? (in dotted decimal) 5) What is the number...
4. Given a network IP address of 130.124.0.0 answer the following questions if 8 subnets are to be created a. What dass (A, B or C) is the IP address 130.124.0.07 b. What is the # of borrowed host bits to create 8 subnets? Show your work and/or explain your answer. c Determine the subnet mask d. Determine the number of usable hosts per subnet e. Determine the network address and the broadcast address for each subnet. Network Address (Subnet)...
Material: Router 1941 Switches 2960 Desktop PCs and Server LAN cables Console cable IPV4 ADDRESSING 1. Divide the 192.168. …… .0 /24 network into equal sized subnets that supports minimum 120 hosts each. (Where the third octet of the IP address has a value of 100 + last 2 digits of your student number) 2. Use the First subnet for the Floor A network. 3. Use the 2nd subnet to create smaller subnets that support minimum 12 hosts each. 4....
Subnet A Subnet B FO/6 PC-A Golo>< 601 R1 Fo/S PC-B $1 Develop the IPv4 Addressing Scheme Given an IP address and mask of 209.165.201.0/24 (address / mask), design an IP addressing scheme that satisfies the following requirements. Work out the subnetting details and: 1. Fill in the Subnetting table with subnets details (20 points) 2. Fill in the Devices Addressing table (5.5 points) Subnet Number of Hosts Subnel A 40 Subnet B 120 Subnet C 5 Subnet D 12...