Question

1. Consider a network with network address 192.168.10.0/24, divide this network into 6 equal size subnets. And find followings

1. Subnet mask

2. Size of a subnet

3. Network addresses of each subnet

4. Broadcast addresses of each subnet

5. First 2 IP addresses of each subnetwork.

2. Answer following questions based on thee values given below

• Number of needed usable hosts in a single sub net - 22
• Network Address - 201.168.75.0

1. Address class  

2. Default mask

3. subnet mask  

4. Number of bits borrowed

5. Total number of subnets

6. Total number of host addresses

7. Number of usable addresses in a single subnet

8. What is the 5^th subnet range?

9. What is the net id of the 5^th subnet?

10. What is the subnet broadcast address for the 4th subnet?

11. What are the first and last assignable addresses for the 3^rd subnet?

Answer 1

Solution

a)

255.255.255.0

b)

254

c)

192.168.10.0

d)

192.168.10.255

e)

192.168.10.1
192.168.10.2

--

Explanation

subnet mask in binary

11111111.11111111.11111111.00000000

to find number of usable host

we need to use

2 ⁿ-2

2 ⁸ -2

256-2

254

--

answered first part of the question

please post remaining question, love to answer

all the best