Question

a recipient of 0.225-L contain CO2 of 295 K and 451 mm Hg. what is the pressure of the CO2 if the volume rises to 0.600L and rhe tempeature rises to 358 K

Answer 1

2

[c= constant] Tz- Final Fantature From the combined Geas Law Knau VL T CT or pv so we cam write for two different PESSUMC, volume temperature conditions Pi Initial pressure PvI P₂ V2 V = Initial volume Ti Tz Ti = Initial Temp creature. P = 45 1mni P₂ = ? P2= Final pressure v=0 225L v2 = 0.600L V2= Final vowme - Ti = 295 K T2 = 358K Temperature

P2 V2 uc Know PV T or 45 mm x 0.225L P2 X OL00L 295K 358K or 451 mm x 02254 P2 x 0°600 358K 2 2954 2 036 P2= 4 51mm x 0°225 x 358 295 X 0° 600 = 2,05°24mm Pressure of co₂ is 205-24 mm Hg.