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Q1: a) The sequence 0,1,1,1,0,1,0,0,1,1,1,0 was produced by a recurrence relation Xn+3=Co Xn+c]Xn+1+c2Xn+2 (mod2) find co, C1
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Solution given x 2 = 1 ta Ny=0 x = 6 Ns - x = 1 22=1 13=1 0 0 xo=1 2ད། 0 n Now x3 = (Coxo + C, X, + C2 X 2 ) mod 2 (0 + 1xc,So Co zodd = even C2 = odd so Co = 1,3,5 aan C = 0, 2, 4, 6- C2 = 1,3,5,- Answel En = Co z 3 C, = 2 C2=3 Knt3 = (3xn+ 2an+1 +

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Q1: a) The sequence 0,1,1,1,0,1,0,0,1,1,1,0 was produced by a recurrence relation Xn+3=Co Xn+c]Xn+1+c2Xn+2 (mod2) find co,...
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