Question

13) Find the probability of selectiny 2 or more girls. A) 0.001 B) 0.999 C) 0.006 D) 0.991 Assume that a procedure yields a binomial distribution with a trial repeated times. Use the binomial probability Formato find the probability of successes given the probability pot success on a single trial. Round to three decimal places. 14) n-6,-3,p- the 14) A) 0.015 50.054 C) 0.032 D) 0.029 . iv . d - 6 15) Find the indicated probability. 15) The brand name of a certain chain of coffee shops has a 53% recognition rate in the town of Coffleton. An executive from the company wants to verify the recognition rate as the company is interested in opening a coffee shop in the town. He selects a random sample of 10 Coffleton residents. Find the probability that the number that recognize the brand name is not 4. A) 0.821 B) 0.0905 C) 0.000851 D) 0.179 16) 16) Suppose that 14% of people are left handed. If 9 people are selected at random, what is the probability that exactly 2 of them are left handed? A) 0.491 B) 0.245 C) 0.0933 D) 0.0196 If z is a standard normal variable, find the probability. 17) The probability that z is less than 1.13 A) 0.8907 B) 0.1292 173 C) 0.8485 D) 0.8708 18) The probability that 2 lies between 0.7 and 1.98 A) 1.7341 B) 0.2175 C) 0.2181 D) -0.2181 and the indicated probability. 10) The incomes of trainees at a local mill are normally distributed with a mean of $1100 and a standard deviation of $150. What percentage of trainees eain less than $900 a month? A) 90.82% B) 35.31% C) 40.82% D) 9.18% 20) A bank's loan officer rates applicants for credit. The ratings are normally distributed with a mean of 200 and a standard deviation of 50. If an applicant is randomly selected, find the probability rating that is between 200 and 275. A) 0.4332 B) 0.5 C) 0.0668 D) 0.9332

Answer 1

Let x be the number of people the brand name that recognize n = 10 P: 0.53 (since 53% recognition rate) 1. P(x=4) i e, Probability that 4 number of - people out of 10 recognize the brand name. XN Binomial (nop) where (2,620 (10,0.51) (Binomis probability distribution 106 - P(X=x) ca (0.53)4(1-053, 0-4 2 210 X0-0789%0.010779 z 0.1786 we require the probability that the number that recognize the brand name is not u. .. PCX74) = 1- P(x=47 - 1- 0.1786 = 0.8214 & TA) 0.621 is correct Answer (16) b=0.14 (prob. of left hander) n=9 (Total number of peoples) bu binomial probability distribution s P(x=x) = (0) 4 (1-bn-x , ne= oil.non 0 <þ<) :: P(X=2) = ( 9) (044)? (1-0.143.9-2

= 36X0.0196 x 0.3479 = 0.2455 :: B10.245 is correct answer 17 . Plz <1:13) F = 0.871 III Standard o 1 (from standard noomal probabilty table) :: 0 0.8708] is corect answer P(0.7<2<1-98) = PLZ<1.98) – P(2<0.7) = 0.976- 0.758 = 0.218 a) 0.218) is correct answer O 0.7 1.98 : ③ Mean M=1100 0 = 150

2222 150 P(x<900) = P(X-4 < 900-4) = P(Z < 900-1100 ) z=x-4 is Standard noomal = PLZ<-1.333) = 0.091 :. 9.18%. [09:18 is correct answer variate -1333 H= 200 o = 50 PC200 <x < 275) - P(-200-He tolle < 276) = P(2002200 << < 2755200) - Plocz < 1.5) = PL2<1.5) -P(220) / SO = 0.933 -0.50 = 0.433 : A) 0.432 l is correct answer * Please ask maximum 4 Question at a time