In scale A, on the left side there are two squares and one circle. On the right side, there are eight triangles.
In scale B, on the left side there are two circles and two squares.On the right side, there are ten triangles.
When we compare both scales, we see that in scale B, as number of circle increases by 1, number of triangle increases by 2 and here number of square is same as that of scale A. So we conclude that 1 circle=2 triangles.
Now if 1 circle is equal to two triangles, then in scale A, 2squres=6 triangles, hence we got 1 square = 3 triangles.
Finally for scale C, there are 5 squares. since 1 square = 3 triangles so 5 squares =15 triangles.
now total number of triangles on left side of scale C is 15+5=20 triangles.
since, 2 triangles = 1 circle, hence 20 triangles = 10 circles.
Therefore there must be 10 circles on right side of scale C.
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a ruby program problem
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