Assume that plant weight is determined by a pair of alleles at each of two degree...
Questions 64-65 refer to the following. In a plant, axial flower (T) is dominant to terminal flower (t) and red fruit color (Y) is dominant to yellow (y). These effects are caused by two independently assorting autosomal genes. An individual terminal red plant was crossed with an individual axial, yellow plant to produce offspring which were 1/2 axial, red: 1/2 terminal, red. The genotype of the crossed terminal red plant was: ttyy ttYy ttYY TTyy Ttyy In the cross described...
1. A series of unlinked genes contribute in an equal manner to determine the number of flowers in an inflorescence for a plant species. Two pure breeding lines, one with 4 flowers and a second with 12 flowers per inflorescence. After the cross is performed the F1 plants have 8 flowers per inflorescence. The F1 plants as crossed with each other and the resulting F2 produces plants with as few as 4 flowers per inflorescence and as many as 12....
4. Assume the database that was used to generate Table 1 consists of 36 individuals. Using this information, what is (show equations and calculations, the probability (report the RMP and combined frequency) that two individuals have the same profile of 15/16; 8/8; 12/13 if (and no, allele 13 is not a typo): a) they are unrelated, but from a smaller demographic, explain use of equation (4 marks) b) there could be a parent-offspring relationship possible, explain use of equation (4...
Please explain these in a way that makes sense as soon as possible
1. Two different autosomal loci (t1 and t2) can render a mouse tailless. The tailless alleles at both loci are recessive. Homozygosity for the recessive allele at either of the loci or at both loci renders the mouse tailless. A tailless mouse homozygous for t1 is mated to a tailless mouse that is homozygous for t2 and produces F1 mice with NORMAL tails. What will be the...
8. Pea plant breeders wanted to pick healthy tall plants that were homozygous for the height gene. They had a collection of 10 plants that were healthy and tall, but the genotypes were unknown. How might they determine if the 10 tall plants were heterozygous or homozygous for the height gene? a. What genotypes are possible for tall pea plants? b. What cross would be most useful in distinguishing between homozygous and heterozygous tall plants? c. Explain the concept of...
For problems 38 and 39 assume that in squashes the difference in fruit weight between a 3-1b type and a 6-lb type results from three independently segregating allele pairs with each capital letter contributing a half pound to the weight of the squash. 38. What is the range in fruit weight of the offspring in the following cross: Aa Bb Cc x Aa Bb Cc 39. A farmer develops a 4-lb variety of the squash that is true breeding. What...
Match the following terms with the appropriate description
below:
a. alleles b. autosomes c. dominant allele d. genotype e.
heterozygous f. homozygote g. phenotype h. recessive allele i. sex
chromosomes
1. ________________ genetic make-up
2. ________________ how genetic make-up is expressed
3. ________________ chromosomes that dictate most body
characteristics
4. ________________ alternative forms of the same gene
5. ___________an individual bearing two alleles that are the same
for a particular trait 6. ________________ an allele that is
expressed, whether in...
Part A Human ABO blood type is determined by three alleles, two of which (and P) produce gene products that modify the H antigen produced by protein activity of an independently assorting H gene. For this cross, what fraction will have type O blood? Express your answer as a fraction. Example: 1/8 For this cross, 4/8 will have type O blood. A rare abnormality known as the "Bombay phenotype" is the result of epistatic interaction between the gene for the...
please help with these questions thank you!
Height Weight BMI Age (years) HeightPercentile Weight Percentile Percentile cm 3.5 97 15.4 115 27 135 46 12 155 75 16 166 Questions to complete for the assignment: 1. What is your assessment of his growth pattern for the following items: a. weight/age b. height/age BMI percentile change over time c. If today's date is February 20, 2018 and his birth date is August 25, 2001, what is his age to date? Please...
Practice questions for BIO 340 (Exam 2) I need help with these
questions Please. WILL GIVE GOOD RATING
1. Wild type blue-eyed mary has blue flowers. Two genes control the pathway that makes the blue pigment: The product of gene W turns a white precursor into magenta pigment. The product of gene M turns the magenta pigment into blue pigment. Each gene has a recessive loss-of-function allele: w and m, respectively. A double heterozygote (Ww Mm) is self-pollinated. What proportion...