Suppose K= 9.4 x 10^-3 at a certain temperature for the reaction PCl5--->PCl3+Cl2. Iif it is found that the concentration of PCl5 is twice the concentration of PCl3, what must be the concentration of Cl2 under these conditions?
Hi,
The equilibrium constant fro this reaction would be
K = [PCl3] [Cl2] / [PCl5]
9.4 * 10^-3 = x [Cl2] / 2x
[Cl2] = 9.4 * 10^-3 * 2 = 18.8 * 10^-3
Suppose K= 9.4 x 10^-3 at a certain temperature for the reaction PCl5--->PCl3+Cl2. Iif it is...
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