Answer :-
Firstly from the given data, van't Hoff factor is calculated then using the formula of degree of dissociation, Ka is calculated.
The answer is given in the image,

A 1.000 m solution of chloroacetic acid (CICH2COOH) freezes at - 1.93°C. Find the Ką of...
1. a pure solvent freezes at 53.0 degree C. A solution of 1.93 g of biphenyl (MM=154.2 g/mol) plus 27.40 g of this solvent freezes at 17.5 degree C. What is Kf for this solvent in Degree C/m 2. A mixture of 2.84 g of unknown plus 29.66 g of benzophenone freezes at 12.0 degrees C. (Pure Benzophenenone freezes at 48.1 degrees C and has a Kf = 98.1 Degree C/m) What is the molar mass of this unknown in...
A 0.595 m aqueous solution of a monoprotic acid (HA) freezes at -2.21°C. Find the pKa of this monoprotic acid. Kf of water = 1.86 °C/m
A 0.61 m aqueous solution of a monoprotic acid (HA) freezes at -1.11°C. Find the pKa of this monoprotic acid. Kf of water = 1.86 °C/m Enter to 3 decimal places.
A 0.70 m aqueous solution of a monoprotic acid (HA) freezes at -1.50°C. Find the Ka of this monoprotic acid. Kf of water = 1.86 °C/m Enter to 4 decimal places.
Chloroacetic acid, HC2H2O2Cl, is a stronger monoprotic acid than acetic acid. In a 0.10 M solution, the pH is 1.96. Calculate the Kafor chloroacetic acid. Calculate the pKa for chloroacetic acid. Use the correct number of significant figures.
Chloroacetic acid, HC2H2O2Cl, is a stronger monoprotic acid than acetic acid. In a 0.10 M solution, the pH is 1.96. Calculate the pKa for chloroacetic acid. pKa =
5.) Calculate the concentrations of all the species and the pH
in 0.25 M hypochlorous acid, HOCL. For HOCL, Ka=3.5x10^-8
6.) the pH of a 0.115M solution of chloroacetic acid,
CICH2COOH, is measured to be 1.85. Calculate the Ka for this
monoprotic acid
Calculate the concentrations of all the species and the pH in 0.25 M hypochlorous acid, HOCI. For HOC, Ka :3.5 x 108. .) The pH of a 0.115M solution of chloroacetic acid, CICH2COOH, is measured to be...
A 25.0 mL sample of 0.150 M chloroacetic acid is titrated with a 0.150 M NaOH solution. What is the pH at the equivalence point? The of chloroacetic acid is 1.4 ×10-3.
Consider a titration of 25.00 mL Chloroacetic Acid solution [ka=1.4x10^-3] with 0.1202 M solution of sodium hydroxide. The volume of 27.40 mL of NaOH(aq) was needed to reach the equivalence point. Calculate: a) The concentration of the chloroacetic acid solution before the titration b) the pH of the chloroacetic acid solution before titration c) the pH of the solution at half equivalence point d) the pH of the solution at the equivalence point e) the pH of the solution when...
A chemistry graduate student is given 125.mL of a 1.40M chloroacetic acid HCH2ClCO2 solution. Chloroacetic acid is a weak acid with =Ka×1.310−3. What mass of KCH2ClCO2 should the student dissolve in the HCH2ClCO2 solution to turn it into a buffer with pH =2.97? You may assume that the volume of the solution doesn't change when the KCH2ClCO2 is dissolved in it. Be sure your answer has a unit symbol, and round it to 2 significant digits.