1. a pure solvent freezes at 53.0 degree C. A solution of 1.93 g of biphenyl (MM=154.2 g/mol) plus 27.40 g of this solvent freezes at 17.5 degree C. What is Kf for this solvent in Degree C/m
2. A mixture of 2.84 g of unknown plus 29.66 g of benzophenone freezes at 12.0 degrees C. (Pure Benzophenenone freezes at 48.1 degrees C and has a Kf = 98.1 Degree C/m)
What is the molar mass of this unknown in g/mol?
1. a pure solvent freezes at 53.0 degree C. A solution of 1.93 g of biphenyl...
A pure solvent freezes at 6.35 degrees Celsius and a pure solute freezes at 832.0 degrees Celsius. The molar mass of the solvent is 96.4 g/mol and the molar mass of the solute is 78.5 g/mol. The freezing point depression constant for the solvent is 6.33 degrees/m. A solution is made of 1.012 g of the solute and 15.280 g of the solvent, determine its freezing point in degrees Celsius.
1h. A certain pure solvent freezes at 39.8°C and has a freezing point depression constant Kf = 0.777°C/m. What is the predicted freezing point (in °C) of a solution made from this solvent that is (1.90x10^0) m in a non-electrolyte solute? 1i. When (8.23x10^1) g of a non-electrolyte is dissolved in (5.2600x10^2) g of a solvent (with Kb = 0.416°C/m) the boiling point of the solution is 1.50°C higher than the boiling point of the pure solvent. What is the...
The melting point of a pure solvent (kf = 1.65 degrees C/m ) is-116.3 degrees C. If 352 g of an ionic solid (i=2.4) is added to 567.7 g of solvent, the new melting point is -121.6 degrees. What is the molar mass of the ionic solute?
I
need this quick please
27. A pure solvent freezes at 43.4°C. The freezing temperature is 40.7°C when 52.5 g of CO(NH-h is in 1.00 x 102 g of the solvent. Calculate the molal freezing point constant of the solvent. (The molar mass for CO(NH2h is 60.06 g/mol.) a. 0.309 °C/m b. 0.343°C/m c. 0.93°C/m d. 13.9°C/m e. 14.9°C/m 28. K-1.3 x 10-10 for the reaction HC,H,O(a)H (aq) + C,H,O (aq). In which direction is the equilibrium favored? a. Forward...
1.A solution that contains 15.581 grams of benzene (molar mass = 78.1 g/mol) in 420 g of cyclohexane freezes at a temperature 9.50 ºC below the freezing point of pure cyclohexane. Calculate the molar freezing point depression constant, Kf, for cyclohexane. 2. The molar boiling point elevation constant for water is 0.512 ºC/m. What is the boiling point of a solution containing 673 g of water and 78.0 g of CaCl2? 3. A solution containing 32.0 g of an unknown...
The freezing point of 53.37 g of a pure solvent is measured to be 49.20 ºC. When 2.74 g of an unknown solute (assume the van 't Hoff factor = 1.0000) is added to the solvent the freezing point is measured to be 47.05 ºC. Answer the following questions ( the freezing point depression constant of the pure solvent is 7.83 ºC·kg solvent/mol solute). What is the molality of the solution? m How many moles of solute are present? mol...
The freezing point of 53.48 g of a pure solvent is measured to be 41.91 ºC. When 2.94 g of an unknown solute (assume the van 't Hoff factor = 1.0000) is added to the solvent the freezing point is measured to be 39.86 ºC. Answer the following questions ( the freezing point depression constant of the pure solvent is 7.33 ºC·kg solvent/mol solute). -What is the molality of the solution?___ m -How many moles of solute are present? ___mol...
Colligative Properties 1a When a solution is made from 25.9 g of an unknown nonelectrolyte dissolved in 167.6 g of solvent, the solution boils at 63.24 °C. The boiling point of the pure solvent and its Kb are 59.02 °C and 2.09 °C/m, respectively. Calculate the molar mass of the unknown electrolyte in g/mol. Report your answer to TWO places past the decimal 1b When a solution is made from 39.5 g of an unknown nonelectrolyte dissolved in 109.1-2.47 °C....
3a. Calculate the molar mass (in g/mol) of an unknown 1:1 electrolyte if 0.482 g dissolved in 223.1 mL of water at 74.75 °C has an osmotic pressure of 54.4 mmHg. R = 0.082058 L⋅atm⋅mol−1⋅K−1. 1.00 atm = 760 mmHg. Report your answer to THREE significant figures. 3b. Calculate the required mass of an unknown nonelectrolyte (ℳ = 131.5599 g/mol) dissolved in 140.1 g of solvent that gives a solution that boils at 36.04 °C. The boiling point of the...
1.0345 g of palmitic acid dissolved in 8.7545 g of stearic acid. Calculate the freezing point of the solution. The molar mass of palmitic acid is 256.48 g/ mol. The molal freezing point constant , Kf for stearic acid is 4.5 degrees C/ m and pure stearic acid freezes at 69.3 degrees Celsius.