Design an algorithm (code in C) that decomposes a natural number into its figures: units, tens, hundreds ... and you store them in a table in reverse,
Empty places will be filled with zeros.
First, you need to determine the size of the table, keeping in mind that the largest natural number that can be represented is: 2 ^ 32 - 1 = 4294967295.
#include <stdio.h>
int main()
{
int table[10];
/*max size of the table will be 10
since largest natural number can be represnted using
10 digits*/
int n,m,i=0,j,rem;
// inializing the table with zero
for(j=0;j<10;j++){
table[j]=0;
}
printf("Enter the natural Number ");
scanf("%d",&n);
m=n; //temporarily storing the value
while(m!=0)
{
rem=m%10; // extracting each
digit
table[i]=rem; // storing the data
in the array(table) which acts as a queue
/* ones digit will be stored in the
first of the array
therefore we are storing the data
in the reverse order*/
i++;
m=m/10;
rem=0;
}
//printing the number in the reverse order
// since we have stored the number in reverse order in
the array
//printing array from the beggining will provide us
the number in the reverse form
printf("\n\nNumber in reverse order\n");
for(j=0;j<i;j++)
{
printf("%d",table[j]);
}
/*note
to print the full table with all 0 also.
in for j loop, modify the condition as j<10
since
the size of the table is 10
*/
return 0;
}


Design an algorithm (code in C) that decomposes a natural number into its figures: units, tens,...
Create a c++ code and answer number 1
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