Question

Colligative Properties

1a

When a solution is made from 25.9 g of an unknown nonelectrolyte dissolved in 167.6 g of solvent, the solution boils at 63.24 °C. The boiling point of the pure solvent and its K_b are 59.02 °C and 2.09 °C/m, respectively. Calculate the molar mass of the unknown electrolyte in g/mol.

Report your answer to TWO places past the decimal

1b

When a solution is made from 39.5 g of an unknown nonelectrolyte dissolved in 109.1-2.47 °C. The freezing point of the pure solvent and its K_f are 3.93 °Cand 4.82 °C/m, respectively. Calculate the molar mass of the unknown electrolyte in g/mol.

Report your answer to TWO places past the decimal.

1c

Calculate the molar mass (in g/mol) of an unknown 1:1 electrolyte if 0.573 gdissolved in 158.7 mL of water at 58.76 °C has an osmotic pressure of 50.3 mmHg.

R = 0.082058 L⋅atm⋅mol⁻¹⋅K⁻¹. 1.00 atm = 760 mmHg. Report your answer to THREE significant figures.

1d

Calculate the freezing point of a solution that is made from 23.6 g of a nonelectrolyte (ℳ = 161.4676 g/mol) dissolved in 144.4 g of solvent. The solvent freezes at 2.30 °C and its K_f value is 2.00 °C/m.

Report your answer to TWO places past the decimal.

1e

Calculate the molar mass (in g/mol) of an unknown nonelectrolyte if 0.968 gdissolved in 228 mL of water at 15.15 °C has an osmotic pressure of 72.5 mmHg.

R = 0.082058 L⋅atm⋅mol⁻¹⋅K⁻¹. 1.00 atm = 760 mmHg. Report your answer to THREE significant figures.

1f.

The solubility of oxygen gas at 25.4 °C and a oxygen pressure of 682 mmHg is 3.72 × 10⁻³ g/L. What is the Henry's Law constant in mol⋅L⁻¹⋅atm⁻¹?

Report your answer to THREE significant figures.

please answer all parts! And leave clear steps as to how to solve/ formulas if you can! Thank you!

Answer 1