Question

3a. Calculate the molar mass (in g/mol) of an unknown 1:1 electrolyte if 0.482 g dissolved...

3a. Calculate the molar mass (in g/mol) of an unknown 1:1 electrolyte if 0.482 g dissolved in 223.1 mL of water at 74.75 °C has an osmotic pressure of 54.4 mmHg. R = 0.082058 L⋅atm⋅mol−1⋅K−1. 1.00 atm = 760 mmHg. Report your answer to THREE significant figures.

3b. Calculate the required mass of an unknown nonelectrolyte (ℳ = 131.5599 g/mol) dissolved in 140.1 g of solvent that gives a solution that boils at 36.04 °C. The boiling point of the pure solvent is 29.40 °C and its Kb value is 3.61 °C/m. Report your answer to TWO places past the decimal.

3c. Calculate the osmotic pressure (in atm) of a solution that is made from 1.07 g of a 1:1 electrolyte (ℳ = 137.9729 g/mol) dissolved in enough water to give 604 mLof solution at 21.44 °C. R = 0.082058 L⋅atm⋅mol−1⋅K−1. Report your answer to THREE significant figures

3d. When a solution is made from 31 g of an unknown nonelectrolyte dissolved in 177.3-9.83 °C. The freezing point of the pure solvent and its Kf are -4.56 °C and 2.84 °C/m, respectively. Calculate the molar mass of the unknown electrolyte in g/mol. Report your answer to TWO places past the decimal.

3e. Calculate the molar mass (in g/mol) of an unknown nonelectrolyte if 0.227 g dissolved in 203.4 mL of water at 17 °C has an osmotic pressure of 62.5 mmHg. R = 0.082058 L⋅atm⋅mol−1⋅K−1. 1.00 atm = 760 mmHg. Report your answer to THREE significant figures.

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
3a. Calculate the molar mass (in g/mol) of an unknown 1:1 electrolyte if 0.482 g dissolved...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Calculate the molar mass (in g/mol) of an unknown 1:1 electrolyte if 0.45 g dissolved in...

    Calculate the molar mass (in g/mol) of an unknown 1:1 electrolyte if 0.45 g dissolved in 199.2 mL of water at 49.72 °C has an osmotic pressure of 34.4 mmHg. R = 0.082058 L⋅atm⋅mol−1⋅K−1. 1.00 atm = 760 mmHg. Report your answer to THREE significant figures.

  • 3a. Calculate the required mass of an unknown nonelectrolyte (ℳ = 125.7998 g/mol) dissolved in 12...

    3a. Calculate the required mass of an unknown nonelectrolyte (ℳ = 125.7998 g/mol) dissolved in 129.7 g of solvent that gives a solution that freezes at 1.85 °C. The freezing point of the pure solvent is 4.44 °C and its Kf value is 1.87 °C/m. Report your answer to TWO places past the decimal. 3b. Calculate the molar mass (in g/mol) of an unknown nonelectrolyte if 0.613 g dissolved in 250.3 mL of water at 19.47 °C has an osmotic...

  • Colligative Properties 1a When a solution is made from 25.9 g of an unknown nonelectrolyte dissolved...

    Colligative Properties 1a When a solution is made from 25.9 g of an unknown nonelectrolyte dissolved in 167.6 g of solvent, the solution boils at 63.24 °C. The boiling point of the pure solvent and its Kb are 59.02 °C and 2.09 °C/m, respectively. Calculate the molar mass of the unknown electrolyte in g/mol. Report your answer to TWO places past the decimal 1b When a solution is made from 39.5 g of an unknown nonelectrolyte dissolved in 109.1-2.47 °C....

  • 2a Calculate the freezing point of a solution that is made from 39.9 g of a...

    2a Calculate the freezing point of a solution that is made from 39.9 g of a nonelectrolyte (ℳ = 142.4701 g/mol) dissolved in 186.3 g of solvent. The solvent freezes at 1.24 °C and its Kf value is 2.09 °C/m. Report your answer to TWO places past the decimal. 2b The solubility of carbon dioxide gas at 37.3 °C and a carbon dioxide pressure of 554 mmHg is 4.04 × 10−3 g/L. What is the Henry's Law constant in mol⋅L−1⋅atm−1?...

  • 1.When a solution is made from 32.2 g of an unknown nonelectrolyte dissolved in 151 g...

    1.When a solution is made from 32.2 g of an unknown nonelectrolyte dissolved in 151 g of solvent, the solution boils at 83.44 °C. The boiling point of the pure solvent and its Kb are 79.31 °C and 4.47 °C/m, respectively. Calculate the molar mass of the unknown electrolyte in g/mol. 2. Calculate the molar mass (in g/mol) of an unknown nonelectrolyte if 0.898 g dissolved in 268.7 mL of water at 30.13 °C has an osmotic pressure of 68.1...

  • Calculate the required mass of an unknown nonelectrolyte (ℳ = 168.0568 g/mol) dissolved in 133.9 g...

    Calculate the required mass of an unknown nonelectrolyte (ℳ = 168.0568 g/mol) dissolved in 133.9 g of solvent that gives a solution that boils at 60.35 °C. The boiling point of the pure solvent is 53.89 °C and its Kb value is 4.40 °C/m. Report your answer to TWO places past the decimal.

  • An unknown strong electrolyte in the form X2Y3 was found to have a molar mass of...

    An unknown strong electrolyte in the form X2Y3 was found to have a molar mass of 262.85g/mol. If 3.58g of the compound is dissolved in enough water to make 175mL of solution at 298K, what is the osmotic pressure of the resulting solution (in atm)?

  • A solution of an unknown nonelectrolyte is formed by adding 1.13 g in 250 mL of...

    A solution of an unknown nonelectrolyte is formed by adding 1.13 g in 250 mL of water. This generates an osmotic pressure of 0.46 atm at 25 °C. Given R = 0.0821 L-atm/K-mol, calculate the molar mass of the nonelectrolyte (to two significant figures). Please explain step-by-step.

  • 100. mL of solution and is found to have an osmotic pressure of 28.1 mmHg at...

    100. mL of solution and is found to have an osmotic pressure of 28.1 mmHg at 20°C. Calculate the molar mass of the compound. (1 atm 760 mmHg) 1 0.102 g of an unknown non electrolyte solute is dissolved in enough water to make A. 663 g/mol B. 0.872 g/mol C. 1.15 g/mol D. 727 g/mol E. 1.10 x 102 g/mol

  • 467. mg of an unknown protein are dissolved in enough solvent to make 5.00 mL of...

    467. mg of an unknown protein are dissolved in enough solvent to make 5.00 mL of solution. The osmotic pressure of this solution is measured to be 0.0930 atm at 25.0 °C. Calculate the molar mass of the protein. Be sure your answer has the correct number of significant digits.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT