Light of wavelength 450 nm falls on a 0.47 mm wide slit and forms a diffraction pattern on a screen 1.7 m away.
(a) Find the position of the first dark band on each side of the central maximum.
mm
(b) Find the width of the central maximum.
mm
given
lamda = 450 nm = 450*10^-9 m
d = 0.47 mm = 0.47*10^-3 m
R = 1.7 m
a) the position of the first dark band on each side of the central maximum,
y1 = lamda*R/d
= 450*10^-9*1.7/(0.47*10^-3)
= 1.63*10^-3 m
= 1.63 mm
b) the width of the central maximum, w = 2*lamda*R/d
= 2*450*10^-9*1.7/(0.47*10^-3)
= 3.26*10^-3 m
= 3.26 mm
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