sodium and calcium
sulfur and sodium
barium and fluorine
sulfur and iodine all of them empirical formula of ionic compound
sodium and calcium :- they both are strong metals so they don't form ionic bonds because ionic bonds are formed between a metal and a non metal .
sulphur and sodium :- sulphur is a divalent non metal and sodium is a monovalent metal ,hence they form ionic bond ( Na2S )
barium and fluorine :- barium being an divalent metal and fluorine being an monovalent non metal hence they form ionic bond ( BaF2)
iodine and sulphur :- they both are non metals ,so they don't form ionic bonds between them
sodium and calcium sulfur and sodium barium and fluorine sulfur and iodine all of them empirical...
5. The elements fluorine (F) and calcium (Ca) form the ionic compound calcium fluoride. a. When fluorine forms an ion, what is its charge? b. When calcium forms an ion, what is its charge? c. Write the empirical formula for the ionic compound formed by fluorine and calcium.
20. A compound of sulfur and fluorine was analyzed and found to contain 70.3% fluorine by mass. What is the empirical formula of the compound and its empirical formula mass?
Predicting ionic compounds formed by two elements Abde Decide whether each pair of elements in the table below will form an ionic compound. If they will, write the empirical formula of the compound formed in the space provided. element #1 element #2 Forms ionic compound? empirical formula of ionic compound Da sulfur iodine yes no X 6 sodium fluorine yes no lithium bromine eyes no O sulfur sodium yes no
Determine whether the following pairs of elements can form ionic compounds Manganese and chlorine fluorine and sodium potassium and sulfur lithium and calcium sulfur and calcium nitrogen and iodine
element #1 element #2 Forms ionic compound? empirical formula of ionic compound magnesium iodine yes no strontium potassium fluorine oxygen yes O yes yes no no no DOO potassium oxygen I Don't Know Submit
Problem Page Decide whether each pair of elements in the table below will form an ionic compound. If they will, write the empirical formula and name of the compound formed in the spaces provided. element #1 element #2 Forms ionic compound? empirical formula of ionic compound name of ionic compound barium lithium yes no sulfur magnesium yes no sulfur fluorine yes no lithium sulfur yes no
A compound is found to contain 31.42 % sulfur, 31.35 % oxygen, and 37.23% fluorine by weight. To answer the questions, enter the elements in the order presented above. 1. What is the empirical formula for this compound? 2. The molecular weight for this compound is 102.1 g/mol. What is the molecular formula for this compound?
Decide whether each pair of elements in the table below will form an ionic compound. If they will, write the empirical formula and name of the compound formed in the spaces provided. element #1 element #2 Forms ionic compound? empirical formula of ionic compound name of ionic compound x s ? iodine magnesium sodium calcium Dyes no O yes no O yes o no O yes no oxygen chlorine sodium oxygen
Decide whether each pair of elements in the table below will form an ionic compound. If they will, write the empirical formula and name of the compound formed in the spaces provided. element #1 element #2 Forms ionic compound? empirical formula of ionic | name of ionic compound compound x magnesium O yes O no 6 ? sulfur rubidium fluorine O yes O no sulfur rubidium O yes no magnesium fluorine O yes O no
ULO E 3 A compound of sodium and sulfur is analyzed to contain following mass of each elements. Calculate is the empirical formula. Show all calculation steps by using conversion factor, give calculator value (c.v.) and Final value (f.v) to get full credit. Show steps (1.2,3) (Na = 5.891 g and S = 4.109 g) 6 pt Step 1: Step 2: Step 3: Empirical Formula is: 4 in the following chemical reaction. Balance the molecular equation by adding coefficier Write...