Question

# A 2700-kg Ferris wheel accelerates from rest to an angular speed of 0.16 rad/s in 14...

A 2700-kg Ferris wheel accelerates from rest to an angular speed of 0.16 rad/s in 14 s . Approximate the Ferris wheel as a circular disk with a radius of 23 m . What is the net torque on the wheel?

Net Torque = _____ m*N

Solution)

Mass,m=2700 kg

Time, t=14 s

Here, Moment of Inertia, I= 0.5 mr^2= 0.5*2700*23^2

=714150 kg-m^2

Also, angular acceleration, alpha=0.16/14= 0.0114 rad/s^2

Now, we know

Torque, T= I*alpha=714150*0.0114= 8161.7 N=8161700 mN (Ans)

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