A 2700-kg Ferris wheel accelerates from rest to an angular speed of 0.16 rad/s in 14 s . Approximate the Ferris wheel as a circular disk with a radius of 23 m . What is the net torque on the wheel?
Net Torque = _____ m*N
Solution)
Mass,m=2700 kg
Angular speed, v=0.16 rad/s
Time, t=14 s
Radius,r=23 m
Here, Moment of Inertia, I= 0.5 mr^2= 0.5*2700*23^2
=714150 kg-m^2
Also, angular acceleration, alpha=0.16/14= 0.0114 rad/s^2
Now, we know
Torque, T= I*alpha=714150*0.0114= 8161.7 N=8161700 mN (Ans)
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