A 50.0kg disk accelerates from rest to an angular speed of 5.00 rad/s in 30.0 seconds....

Question

Question

A 50.0kg disk accelerates from rest to an angular speed of 5.00 rad/s in 30.0 seconds. The disk's diameter is 20.0 meters.

a. Calculate the disk's moment of inertia in kgm^2.

b. Calculate the disk's angular acceleration in rad/s^2

c. Calculate the net torque mN required to accelerate the disk.

Please show all steps

science physics

Answer 1

Answer #1

Moment of inertia of disk=0.5 m r^2=0.5 ×50× 10^2= 2500 kg m^2

Angular acceleration=5/30=1/6 rad/ sec ^2

Torque=1/6×2500=416.66

Answer 2

Similar Homework Help Questions

A 2700-kg Ferris wheel accelerates from rest to an angular speed of 0.16 rad/s in 14...

A 2700-kg Ferris wheel accelerates from rest to an angular speed of 0.16 rad/s in 14 s . Approximate the Ferris wheel as a circular disk with a radius of 23 m . What is the net torque on the wheel? Net Torque = _____ m*N
A disk rotates about its central axis starting from rest and accelerates with constant angular acceleration....

A disk rotates about its central axis starting from rest and accelerates with constant angular acceleration. At one time it is rotating at 11 rad/s; 75 radians later, its angular speed is 22 rad/s. Calculate (a) the angular acceleration (rad/s^2), (b) the time required to complete the 75 radians, (c) the time required to reach the 11 rad/s angular speed, and (d) the number of radians from rest until the time the disk reaches the 11 rad/s angular speed.
A disk I=1/2MR^2 rotating at 1.0 rad/s accelerates to 5.0 rad/s while turning 10 radians. What...

A disk I=1/2MR^2 rotating at 1.0 rad/s accelerates to 5.0 rad/s while turning 10 radians. What is the disk's angular acceleration?

Starting from rest, a 10.06-cm-diameter compact disk takes 8.5 s to reach its operating angular velocity...

Starting from rest, a 10.06-cm-diameter compact disk takes 8.5 s to reach its operating angular velocity of 2381 rpm. Assume that the angular acceleration is constant. The disk�s moment of inertia is 1.00×10-5 kg·m2. How much torque is applied to the disk? 0.0003 N*m How many revolutions does it make before reaching full speed?
2. The disk starts from rest and is given an angular acceleration a = (21) rad/s,...

2. The disk starts from rest and is given an angular acceleration a = (21) rad/s, where 1 is in seconds. Determine the angular velocity of the disk and its angular displacement when 1 = 4 s.
A merry-go-round accelerates from rest to 0.68 rad/s in 24 s. Assuming the merry-go-round is a uniform disk of radius...

A merry-go-round accelerates from rest to 0.68 rad/s in 24 s. Assuming the merry-go-round is a uniform disk of radius 7 m and mass 31000 kg, calculate the net torque required to accelerate it.

Starting from rest, a 12-cm-diameter compact disk takes 2.9s to reach its operating angular velocity of...

Starting from rest, a 12-cm-diameter compact disk takes 2.9s to reach its operating angular velocity of 2500rpm . Assume that the angular acceleration is constant. The disk's moment of inertia is 2.5
A certain merry go round is accelerated uniformly from rest and attains an angular speed of...

A certain merry go round is accelerated uniformly from rest and attains an angular speed of 1.2 rad/s in the first 18 seconds. Also given (if needed): Net applied torque is 1200 Nm Moment of inertia is 18181 kg•m^2 Kinetic Energy is 13090 J Assuming friction is negligible, how much work does the motor have to do to accelerate the merry go round up to 1.2 rad/s? How much power does the motor have to generate to accelerate the merry...
A flat, uniform disk of mass 0.400 kg has a radius of 0.130 m. It accelerates...

A flat, uniform disk of mass 0.400 kg has a radius of 0.130 m. It accelerates from an angular speed of 85 rad/s to 262 rad/s in 18.0 s . Calculate the Moment of Inertia . Calculate the applied torque.

A disk rotates about its central axis starting from rest and accelerates with constant angular acceleration....

A disk rotates about its central axis starting from rest and accelerates with constant angular acceleration. At one time it is rotating at 4.20 rev/s; 75.0 revolutions later, its angular speed is 23.0 rev/s. Calculate (a) the angular acceleration (rev/s2), (b) the time required to complete the 75.0 revolutions, (c) the time required to reach the 4.20 rev/s angular speed, and (d) the number of revolutions from rest until the time the disk reaches the 4.20 rev/s angular speed. _...