In order to find a 86% confidence interval we need to find values a and b such that for Z∼N(μ=0,σ=1),
P(a<Z<b)=0.86.
(a) Suppose a=−2.2475. Then b=
Z∼N(μ = 0,σ = 1),
P(a < Z < b) = 0.86.
a = - 2.2475
We have to find value of b.
P(a < Z < b) = 0.86
P( - 2.2475 < Z < b) = 0.86
P(Z < b) - P(Z < - 2.2475) = 0.86
P(Z < b) - 0.0123 = 0.86
P(Z < b) = 0.86 + 0.0123
P(Z < b) = 0.8723
b = 1.1374
In order to find a 86% confidence interval we need to find values a and b...
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