Question

please add comments and make the progrom work with negative and simple as much as possible

Write a C program utilizing printf and scanf (do not use cout or cin) that does the following:

0. Using the division algorithm introduced in class to convert between base 10 and any other number base:

1. Prompts the user to enter an unsigned integer in base 10 (decimal) from the keyboard.

2. Prompts the user a new base ( greater than or equal to 2 and less than or equal to 36** ) to convert the base 10 unsigned integer into (do not allow values less than 2 or greater than 36, if the user enters a value out of this range, prompt them to re-enter a base).

3. Constructs a string of digits that represents the user entered base 10 integer in the user entered new base.

4. Output the constructed string (do this as a char array of 32 digits instead of the C++ string class [makes possible converting to Assembly Language much easier]).

** for bases greater than 10, you will want to follow the notation that hexadecimal does (10=A, 11=B, 12=C, 13=D, 14=E, 15=F ) meaning that a base 36 number system, the number 35 would be represented with Z.

also your program can properly handle negative values for the number you are converting)

Here are some test cases for your program:

----------------------------------------------------------------------------------------

Enter the base 10 number you would like to convert: 12345

Enter the base you would like to convert 12345 to: 16

12345 base 10 is 3039 base 16

----------------------------------------------------------------------------------------

Enter the base 10 number you would like to convert: 123456

Enter the base you would like to convert 123456 to: 19

123456 base 10 is HIID base 19

---------------------------------------------------------------------------------------

Enter the base 10 number you would like to convert: 123456789

Enter the base you would like to convert 123456789 to: 32

123456789 base 10 is 3LNJ8L base 32

------------------Negative Number Example -------------------

Enter the base 10 number you would like to convert: -1234567

Enter the base you would like to convert -1234567 to: 9

-1234567 base 10 is 88888888888888888888888886607438 ba

Answer 1

from the given data

# include < stdio.h >

# include < string.h>

void base 10 ti any base(
int num, int base, char * converted _str)

{

int index = 0;

int length =0;

int rem = 0;

char result (32) = {0};

// loop till num is greater than 0

while (num > 0)

{

rem = ( num % base);

// calculate remainder using modulus operator

num = num/ base

// divide the number by base

if (base >= 16 && rem > 9)

// if base is >= 16 and remainder > 9

result (index ++) = rem + `A` -10;

// add ascii value of A and subtract 10 to offset 0-9

else

result (index ++) = rem + `0`;

// remainder <= 9, just add ascii value `0`

}

// ned to reverse the result to get correct converted string

// loop till index > 0, index is length of the result string

while (index > 0)

{

// put the character starting from index to 0 in converted _str from 0

// increment length and decrement index

converted_str(length++) = result (-- index);

}

}

int main()

{

int num = 0;

int base = 0;

char converted _str (32) =(0);

// prompt for base 10 number

printf(" \n Enter the base 10 number you would like to convert;");

scanf("%d", & num);

// loop till valid base not entered

while (1)

{

// prompt for base value

printf(" Enter the base you would like to convert %d to : ", num);

scanf("%d", & base);

if (!(base > = 2 && base <= 36))

{

// continue if invalid base entered

printf(" invalid base value. please enter the base >= 2 and <= 36);

continue;

}

else

{

break;

}

}

return0;

}