Question

Write a C program that determines the sum of the decimal digits that appear in the command line arguments (excluding argv[0]) of the main function. The sum should be zero if there are no command line arguments following argv[0], or if the command line arguments following argv[0] do not include any decimal digits.

Example

If the command line arguments (following argv[0]) were

• 7M3 3DoorsDown Sum41 U2 The4Seasons Maroon5 TheB52s

then the sum would be

• 7 + 3 + 3 + 4 + 1 + 2 + 4 + 5 + 5 + 2   =   36

Answer 1

Please find the answer below:

#include <stdio.h>
#include <string.h>
int main(int argc, char *argv[]){
   int sum = 0;
   int i=0;
   int first = 1;
   for(i=1;i<argc;i++){
       int index = 0;
       for(index=0;index<strlen(argv[i]);index++){
           if(argv[i][index]>='0' && argv[i][index]<='9'){
               sum+=argv[i][index]-'0';
               if(first==1){
                   printf("%c ",argv[i][index]);
                   first = 0;
               }else{
                   printf("+ %c ",argv[i][index]);
               }
           }
       }
   }
   printf(" = %d",sum);
   return 0;
}

output: