Calculate the molality NH3 (17 g/mol) in a 5.05% (w/w) aqueous solution. (dsoln = 0.9651 g/mL) three sig figs
5.05 w/w % means
5.05 g NH3 present in 100 g solution
mass of solute = 5.05
mass of solvent = 100 - 5.05 = 94.95 g
molality = (W /MW) (1000 / mass of solvent in g)
molality = (5.05 / 17) (1000 / 94.95)
molality = 3.13 m
Calculate the molality NH3 (17 g/mol) in a 5.05% (w/w) aqueous solution. (dsoln = 0.9651 g/mL)...
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